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masha68 [24]
3 years ago
11

How to solve the equations

Mathematics
1 answer:
Arada [10]3 years ago
7 0
So first off, we need to establish that there are three terms that we need to find: a, c & E.

Let's write the three equations below:

Equation No. 1 -
a + c - 2E = 2

Equation No. 2 -
a - 2c = 5

Equation No. 3 -
- c + E = 4

To begin working out our answer, we will make (a) the subject of our second equation & (E) the subject of the third equation so that we can substitute them into the first equation as displayed below:

Equation No. 2 -
a - 2c = 5
a = 5 + 2c

Equation No. 3 -
- c + E = 4
E - c = 4
E = 4 + c

From there, we substitute the given equations for (a) & (E) into the first equation in order to make (c) the subject in the first equation as displayed below:

Equation No. 1 -
a + c - 2E = 2
( 5 + 2c ) + c - 2 ( 4 + c ) = 2
5 + 3c - 8 - 2c = 2
3c - 2c = 2 - 5 + 8
c = 5

Extending from this, by substituting the value of c, which is 5, into Equation No. 2 & 3, we will be able to also obtain the values of both (a) & (E) as displayed below:

Equation No. 2 -
a = 5 + 2c
a = 5 + 2 ( 5 )
a = 5 + 10
a = 15

Equation No. 3 -
E = 4 + c
E = 4 + ( 5 )
E = 9

Therefore, we have now successfully found the values of a, c & E as displayed below:

a = 15
c = 5
E = 9

If you want to check your answer, then simply substitue the values into Equation No. 1. If after solving the equations, the left-hand & right-hand side are equivalent, then the answer is correct. However, if it isn't equivalent, then the answer is either incorrect or you have made an error while solving thr equation. Here is the working out to check your answer for this question:

a + c - 2E = 2
( 15 ) + ( 5 ) - 2 ( 9 ) = 2
20 - 18 = 2
2 = 2

Therefore, the solution is correct.
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True true true true
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Completely simplified the expression for x plus 10 plus 6 x plus 2 x by combining like terms into your answer in the box.
siniylev [52]
We can first turn the text into a proper formula:

x plus 10 plus 6 x plus 2 x

x+10+6x+2x

The like terms are the numbers with

We can then put the like terms together to continue the calculation:

x+6x+2x+10

=9x + 10

Therefore, the answer is 9x + 10.

Hope it helps!
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2 years ago
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A restaurant menu offers four main courses: grilled chicken, hamburger, hot dog, or pasta. The menu offers three side dishes: sa
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Answer:

36

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3 years ago
hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and
Mariulka [41]

Given:

The equation is,

2\log _3x-\log _3(x-2)=2

Explanation:

Simplify the equation by using logarthimic property.

\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{      \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}

Simplify further.

\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}

Solve the quadratic equation for x.

\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

\begin{gathered} x-6=0 \\ x=6 \end{gathered}

For (x - 3) = 0,

\begin{gathered} x-3=0 \\ x=3 \end{gathered}

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0
1 year ago
In 1981, the Australian humpback whale population was 350 and has increased at a rate of 14% each year since then.)
dimulka [17.4K]

Answer:

In 1981, the Australian humpback whale population was 350

Po = Initial population = 350

rate of increase = 14% annually

P(t) = Po*(1.14)^t

P(t) = 350*(1.14)^t

Where

t = number of years that have passed since 1981

Year 2000

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P(19) = 350*(1.14)^19

P(19) = 350*12.055

P(19) = 4219.49

P(19) ≈ 4219

Year 2018

2018 - 1981 = 37 years

P(37) = 350*(1.14)^37

P(37) = 350*127.4909

P(37) = 44621.84

P(37) ≈ 44622

There would be about  44622  humpback whales in the year 2018

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3 years ago
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