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Juli2301 [7.4K]
3 years ago
7

6. Can an object accelerate, but not speed up or slow down? Explain:

Physics
1 answer:
FromTheMoon [43]3 years ago
5 0

Answer:

yes, though the speed may stay constant, the direction will change. so for example, you're going 70mph on the freeway, but you have to take the exit on your right (the exit continues on to a different freeway), you're not going to speed up or slow down, you'll change your direction which is still accelerating.

Explanation:

Credit goes to @naeAF

Hope this helps :))

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Only four forces act on an object. They all have the same magnitude. Their directions are north, south, northwest, and northeast
mina [271]

Answer:

the correct answer is A,   North

Explanation:

The forces are vectors so they must be added vectorially.

The magnitude of the forces is the same, but not their direction, which is why they are different.

Analyze the situation presented

We have a force towards the North and another towards the South with the same magnitude, therefore these cancel each other out

We have a force towards the Northeast and another towards the Northwest, these can be decomposed into parts, one towards the North and another on the East-West axis, this last component is canceled, but the component towards the North is added.

In summary we see that the body accelerates towards the North

the correct answer is A

7 0
3 years ago
Consider a system of an 85.0 kg man, his 14.5-kg dog, and the earth. The gravitational potential energy of the system increases
Andrew [12]

Answer:

Explanation:

Increase in gravitational potential energy = m x g x h

where m is mass , g is gravitational acceleration and h is height

In the first case when man climbs

increase in potential = 85 x g x h = 1.85 x 10³ J

gh = 21.7647

when dog climbs

increase in potential = 14.5 x g x h  J

= 14.5 x 21.7647

= 315.6 J

6 0
3 years ago
How did this formula come about? Please show me the formula derivation process
kirill [66]

Answer:

so simple it is a square formula

6 0
3 years ago
A basketball player makes a jump shot. the 0.583 kg ball is released at a height of 1.80 m above the floor with a speed of 7.29
Mamont248 [21]
The kinetic and potential energies must be taken into account.  The ball lost some speed but was also raised in the vertical direction between the two measured positions.  This will cost some of the kinetic energy that we don't want to ascribe to the air resistance losses.
The gain in potential energy is 
mg(h₂-h₁) = 0.583*9.81*(3.10-1.80) = 7.435J
The loss in kinetic energy is
(1/2)m(v₁² - v₂²) = (0.583/2)(7.29²-4.22²)=10.3J
Since 7.435J of this is due to the fact that it gained potential energy the final result is E=10.3J-7.435J=2.865J.

One way to think about the potential energy part is that it is higher in the air at the hoop than when the player releases the ball.  In other words it hasn't fallen as far down as it went up, it is still in the process of gaining speed on the way down. This reduction in speed means less kinetic energy, but not because it was lost.  It will be gained once it falls to the height of 1.8m, minus the little loss it will experience over that distance due to air resistance.
5 0
3 years ago
Madison pushes with a 210-N horizontal force on a 24-kg crate of coffee resting on a warehouse floor. The force of friction on t
kotykmax [81]

Answer:

5.7 m/s^2

Explanation:

First of all, we need to calculate the resultant force on the crate. We have:

- A force of +210 N in the positive direction

- The frictional force of -74 N in the opposite direction

So, the resultant force is

F = 210 N - 74 N= 136 N

So now we can apply Newton's second law to find the acceleration:

F=ma

where m=24 kg is the mass of the crate. Re-arranging the equation, we get:

a=\frac{F}{m}=\frac{136 N}{24 kg}=5.7 m/s^2

5 0
3 years ago
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