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sdas [7]
2 years ago
8

A coil is wrapped with 332 turns of wire on the perimeter of a circular frame (of radius 30 cm). Each turn has the same area, eq

ual to that of the frame. A uniform magnetic field is directed perpendicular to the plane of the coil. This field changes at a constant rate from 29 mT to 56 mT in 63 ms. What is the magnitude of the induced average E in the coil, over the time interval 63 ms during which the field changes
Physics
1 answer:
almond37 [142]2 years ago
4 0

Answer:

E=84.5V

Explanation:

From the question we are told that:

Number of Turns N=332turns

Radius r= 30cm

Field Change B=56mt-29mt=27mt

Time t=63ms

Generally the equation for Magnetic Field is mathematically given by

 \frac{dB}{dt}=\frac{27*10^{-3}}{29*10^{-3}}

 \frac{dB}{dt}=0.9T/s

Generally the Flux at 332 turns is  mathematically given by

 \phi=N*A*B

Generally the equation for Area of coil is mathematically given by

 A=\pi*r^2

 A=\pi*(r*10^{-2})^2

Since

 \phi=332*\pi*(\theta*10^{-2})^2*B

Therefore

 \frac{d \phi}{dt}=332*\pi*(900*10^{-4}*\frac{dB}{dt}

Generally the equation for emf Magnitude is mathematically given by

 E=\frac{d\phi}{dt}

 E=332*\pi*(900*10^{-4}*0.9

 E=84.5V

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