Answer:
v = 19.2 m/s
Explanation:
In order to find the speed of the string you use the following formula:
(1)
f: frequency of the string = 80.0Hz
v: speed of the wave = ?
L: length of the string = 12.0cm = 0.12m
The length of the string coincides with the wavelength of the wave for the fundamental mode.
Then, you solve for v in the equation (1), and replace the values of the other parameters:

The speed of the wave is 19.2 m/s
Plant and animal life, atmosphere and water are the major causes of weathering .
Answer:
the impulse experienced by the egg is 0.053 kgm/s.
Explanation:
Given;
mass of the egg, m = 60 g = 0.06 kg
initial velocity of the egg, u = 6 m/s
height moved by the egg, h = 50 cm = 0.5 m
Determine the final velocity of the egg as it moves upward;
v² = u² + 2(-g)h
v² = u² - 2gh
where;
v is the final velocity
-g is negative acceleration due gravity as it moves upward
v² = 6² - 2(9.8 x 0.5)
v² = 26.2
v = √26.2
v = 5.12 m/s
The impulse applied to the egg is the change in linear momentum;
J = ΔP
ΔP = mu - mv
ΔP = m(u - v)
ΔP = 0.06(6 - 5.12)
ΔP = 0.053 kgm/s
Therefore, the impulse experienced by the egg is 0.053 kgm/s.
Answer:
The distance between first-order and second-order bright fringes is 12.66mm.
Explanation:
The physicist Thomas Young establishes through its double slit experiment a relationship between the interference (constructive or destructive) of a wave, the separation between the slits, the distance between the two slits to the screen and the wavelength.
(1)
Where
is the distance between two adjacent maxima, L is the distance of the screen from the slits,
is the wavelength and d is the separation between the slits.
The values for this particular case are:



Notice that is necessary to express L and
in units of milimeters.
⇒ 
⇒ 
Finally, equation 1 can be used:
Hence, the distance between first-order and second-order bright fringes is 12.66mm.
Yes it depend course you throw the stone at the roof it can't came course it in the roof