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Stolb23 [73]
3 years ago
11

Un niño amarra una soga a una piedra, y la hace girar como en la gráfica. la piedra realiza un M.C.U, girando con una rapidez de

14 rad/s. calcular el ángulo que barre en 4 segundos.
Physics
1 answer:
inessss [21]3 years ago
4 0

Answer:

\Delta \theta = 56\,rad

\Delta \theta \approx 3208.564^{\circ}

Explanation:

El ángulo barrido en el intervalo de tiempo dado es (The covered angle in the given time interval is):

\Delta \theta = \omega \cdot \Delta t

\Delta \theta = \left(14\,\frac{rad}{s} \rjght)\cdot (4\,s)

\Delta \theta = 56\,rad

\Delta \theta \approx 3208.564^{\circ}

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A standing wave on a string that is fixed at both ends has frequency 80.0 Hz. The distance between adjacent antinodes of the sta
OlgaM077 [116]

Answer:

v = 19.2 m/s

Explanation:

In order to find the speed of the string you use the following formula:

f=\frac{v}{2L}          (1)

f: frequency of the string = 80.0Hz

v: speed of the wave = ?

L: length of the string = 12.0cm = 0.12m

The length of the string coincides with the wavelength of the wave for the fundamental mode.

Then, you solve for v in the equation (1), and replace the values of the other parameters:

v=2Lf=2(0.12m)(80.0Hz)=19.2\frac{m}{s}

The speed of the wave is 19.2 m/s

8 0
4 years ago
What is the cause of weathering
iren2701 [21]
Plant and animal life, atmosphere and water are the major causes of weathering .
5 0
3 years ago
Read 2 more answers
9. During an egg toss, a catcher must cushion the egg by maximizing the time it takes to stop the
Lorico [155]

Answer:

the impulse experienced by the egg is 0.053 kgm/s.

Explanation:

Given;

mass of the egg, m = 60 g = 0.06 kg

initial velocity of the egg, u = 6 m/s

height moved by the egg, h = 50 cm = 0.5 m

Determine the final velocity of the egg as it moves upward;

v² = u² + 2(-g)h

v² = u² - 2gh

where;

v is the final velocity

-g is negative acceleration due gravity as it moves upward

v² = 6² - 2(9.8 x 0.5)

v² = 26.2

v = √26.2

v = 5.12 m/s

The impulse applied to the egg is the change in linear momentum;

J = ΔP

ΔP = mu - mv

ΔP = m(u - v)

ΔP = 0.06(6 - 5.12)

ΔP = 0.053 kgm/s

Therefore, the impulse experienced by the egg is 0.053 kgm/s.

8 0
3 years ago
7. A double-slit experiment uses coherent light of wavelength 633 nm with a slit separation of 0.100 mm and a screen placed 2.0
Illusion [34]

Answer:

The distance between first-order and second-order bright fringes is 12.66mm.

Explanation:

The physicist Thomas Young establishes through its double slit experiment a relationship between the interference (constructive or destructive) of a wave, the separation between the slits, the distance between the two slits to the screen and the wavelength.

\Lambda x = L\frac{\lambda}{d}  (1)

Where \Lambda x is the distance between two adjacent maxima, L is the distance of the screen from the slits, \lambda is the wavelength and d is the separation between the slits.  

The values for this particular case are:

L = 2.0m

\lambda = 633nm

d = 0.100mm

Notice that is necessary to express L and \lambda in units of milimeters.

L = 2.0m \cdot \frac{1000mm}{1m} ⇒ 2000mm

\lambda = 633nm \cdot \frac{1mm}{1x10^{6}nm} ⇒ 6.33x10^{-4}mm

Finally, equation 1 can be used:

\Lambda x = (2000mm)\frac{(6.33x10^{-4}mm)}{(0.100mm)}

\Lambda x = 12.66mm

Hence, the distance between first-order and second-order bright fringes is 12.66mm.

8 0
3 years ago
A stone is thrown vertically upward from the roof of the building. Does the position of the stone depend on the location chosen
mel-nik [20]
Yes it depend course you throw the stone at the roof it can't came course it in the roof
7 0
4 years ago
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