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Stolb23 [73]
3 years ago
11

Un niño amarra una soga a una piedra, y la hace girar como en la gráfica. la piedra realiza un M.C.U, girando con una rapidez de

14 rad/s. calcular el ángulo que barre en 4 segundos.
Physics
1 answer:
inessss [21]3 years ago
4 0

Answer:

\Delta \theta = 56\,rad

\Delta \theta \approx 3208.564^{\circ}

Explanation:

El ángulo barrido en el intervalo de tiempo dado es (The covered angle in the given time interval is):

\Delta \theta = \omega \cdot \Delta t

\Delta \theta = \left(14\,\frac{rad}{s} \rjght)\cdot (4\,s)

\Delta \theta = 56\,rad

\Delta \theta \approx 3208.564^{\circ}

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Why are we not able to see immediate after we enter a dark hall from a lighter place.
Kipish [7]
Technically this is a Biology question;

The 'amount' we can see depends on how much light can get through our pupil to hit our retina.
When there is a lot of light the pupil is small; it doesn't need to be big to let a lot of light in.
When we move to a dark space there is much less light, so the pupil 'dilates' to let enough light so we can see properly.
The period in which one cant see is simply when the pupil hasn't had time to change shape yet so doesn't let in enough light.<span />
3 0
3 years ago
When testing a home for radon, where is the most likely place for the highest detected level? A) the basement, due to ground see
german

Answer:

A

Explanation:

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5 0
3 years ago
Read 2 more answers
A test charge of -1.4 x 10-7 coulombs experiences a force of 5.4 x 10-1 newtons. Calculate the magnitude of the electric field c
VARVARA [1.3K]

Answer:

3.86×10⁶ Newton/coulombs

Explaination:

Applying,

E = F/q....................... Equation 1

Where E = Electric Field, F  = Force, q = charge.

From the question,

Given: F = 5.4×10⁻¹ N, q = -1.4×10⁻⁷ coulombs

Substitute these values into equation 1

E = 5.4×10⁻¹/ -1.4×10⁻⁷

E = -3.86×10⁶ Newtons/coulombs

Hence the magnitude of the electric field created by the

negative test charge is 3.86×10⁶ Newton/coulombs

5 0
3 years ago
1. You discover that your iPod batteries keep dying after a few days. You think that the new 48 hour iBattery will work better.
stiks02 [169]

Answer:

Explanation:

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7 0
3 years ago
Find the period of the leg of a man who is 1.83 m in height with a mass of 67 kg. The moment of inertia of a cylinder rotating a
cupoosta [38]

Answer:

2.2 s

Explanation:

Using the equation for the period of a physical pendulum, T = 2π√(I/mgh) where I = moment of inertia of leg about perpendicular axis at one point =  mL²/3 where m = mass of man = 67 kg and L = height of man = 1.83 m, g = acceleration due to gravity = 9.8 m/s² and h = distance of leg from center of gravity of man = L/2 (center of gravity of a cylinder)

So, T = 2π√(I/mgh)

T = 2π√(mL²/3 /mgL/2)

T = 2π√(2L/3g)

substituting the values of the variables into the equation, we have

T = 2π√(2L/3g)

T = 2π√(2 × 1.83 m/(3 × 9.8 m/s² ))

T = 2π√(3.66 m/(29.4 m/s² ))

T = 2π√(0.1245 s² ))

T = 2π(0.353 s)

T = 2.22 s

T ≅ 2.2 s

So, the period of the man's leg is 2.2 s

7 0
3 years ago
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