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xxMikexx [17]
3 years ago
15

What role does voltage play in the formation or use of an electromagnet?

Physics
2 answers:
12345 [234]3 years ago
7 0

Answer and explanation;

-Voltage overcomes the resistance of the electromagnet winding to force a current through that resistance. The field strength is proportional to the coil current. More voltage pushes more current.

-There is also a time component of this process, with voltage being needed to build up the magnetic field in a certain time. More voltage builds up the current faster, as well as forcing it to a higher final value.

-When the electromagnet are wound with superconducting wire (with zero resistance) then it would take no voltage to keep current passing through the winding and once it was built up, you could just short the ends together and the current would keep going.

Dafna11 [192]3 years ago
3 0
<span>Voltage overcomes the resistance of the electromagnet winding to force a current through that resistance. The field strength is proportional to the coil current. More voltage pushes more current. More voltage builds up the current faster, as well as forcing it to a higher final value. </span>
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Answer:

Wavelength

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3 years ago
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Jon and Jim push a dead car forward to the gas station. Jon pushes with 90N while Jim pushes 80 N.
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The resultant of the two forces is about 170 N.

<h3>What is the resultant force?</h3>

The term resultant force has to do with the single force that has the same magnitude and direction as two or more forces acting together.

In this case, the both forces are acting in the forward direction. This implies that the resultant force is 90 N  + 80 N = 170 N.

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2 years ago
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Masja [62]

What metal is not at room temperature?

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2 years ago
What area must the plates of a capacitor be if they have a charge of 5.7uC and an electric field of 3.1 kV/mm between them? O 0.
kirill [66]

Answer:

Area of the plates of a capacitor, A = 0.208 m²

Explanation:

It is given that,

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The electric field of a parallel plates capacitor is given by :

E=\dfrac{q}{A\epsilon_o}

A=\dfrac{q}{E\epsilon_o}

A=\dfrac{5.7\times 10^{-6}\ C}{3100000\ V/m\times 8.85\times 10^{-12}\ F/m}

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So, the area of the plates of a capacitor is 0.208 m². Hence, this is the required solution.

8 0
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