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BigorU [14]
3 years ago
10

What would happen if The DNA code in a daughter cell did not match the code in the parent cell

Physics
2 answers:
Vladimir [108]3 years ago
8 0
A mutation would occur if the DNA code in a daughter cell did not match the code in the parent cell.
Hunter-Best [27]3 years ago
5 0
Genetic mutation!!!!!
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When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees
dolphi86 [110]

Answer:

a) 1.725*10^5 N

b) 3.83*10^3 N

c) i) 173.24 kN

c) ii) 4.57 kN

Explanation:

See the attachment for calculations

6 0
2 years ago
When analyzing a position time graph the direction of the slope positive or negative tells us:
Sphinxa [80]

Answer:

Explanation:

Positive values for position indicate that the object is in front of the starting point and negative values tell us that the object is behind the starting point. (time = 9.5, position = 0) the object is at the starting point.

8 0
3 years ago
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Which best contrasts Newton's and Einstein's ideas?
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Answer:

Newton believed that mass tells gravity how much force to exert. Einstein believed that mass tells space-time how to curve.

Explanation:

Isaac Newton believed that bodies on earth had a force of gravity pulling them down as a result of their masses.

Albert Einstein believed that the bodies were not pulled down but were moving around in a circular sphere/manner.

This confirms Newton believing that mass tells gravity how much force to exert and Einstein believing that mass tells space-time how to curve.

6 0
3 years ago
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The voltage drop across any component is
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Answer:

The voltage si the nevery Hokage de Naruto y fue su amigo

7 0
2 years ago
A heat pump with a COP of 3.15 is used to heat an air-tight house. When running, the heat pump consumes 5 kW of power. If the te
Jet001 [13]

Answer: 1026s, 17.1m

Explanation:

Given

COP of heat pump = 3.15

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Initial temperature, T1 = 7°C

Final temperature, T2 = 22°C

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The amount of heat needed to increase temperature in the house,

Q = mcΔT

Q = 1500 * 0.718 * (22 - 7)

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Q = 16155

Rate at which heat is supplied to the house is

Q' = COP * W

Q' = 3.15 * 5

Q' = 15.75

Time required to raise the temperature is

Δt = Q/Q'

Δt = 16155 / 15.75

Δt = 1025.7 s

Δt ~ 1026 s

Δt ~ 17.1 min

5 0
3 years ago
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