All categories

3 years ago

Determine how potential and kinetic energy changes at each position of the pendulum as the ball swings from A to E.

Physics

2 answers:

Andru [333]3 years ago

5 0

Answer:

Explanation:

Determine how potential and kinetic energy changes at each position of the pendulum as the ball swings from A to E.

Position A: is all potential

Position B: losing pot and gaining k

Position C: is all k

Position D: is losing k and gaining pot

Position E: is all pot

100% right

LuckyWell [14K]3 years ago

3 0

At mean position,the entire energy is kinetic and at the extreme positions, it is potential

You might be interested in

You have a double slit experiment, with the distance between the two slits to be 0.025 cm. A screern is 120 cm behind the double

dimulka [17.4K]

Answer:

The wavelength of the light is 633 nm.

Explanation:

Given that,

Distance between the two slits d= 0.025 cm

Distance between the screen and slits D = 120 cm

Distance between the slits y= 1.52 cm

We need to calculate the angle

Using formula of double slit

$\tan\theta=\dfrac{y}{D}$

Where, y = Distance between the slits

D = Distance between the screen and slits

Put the value into the formula

$\tan\theta=\dfrac{1.52}{120}$

$\theta=\tan^{-1}\dfrac{1.52}{120}$

$\theta=0.725$

We need to calculate the wavelength

Using formula of wavelength

$d\sin\theta=n\lambda$

Put the value into the formula

$0.025\times\sin0.725=5\times\lambda$

$\lambda=\dfrac{0.025\times10^{-2}\times\sin0.725}{5}$

$\lambda=6.326\times10^{-7}\ m$

$\lambda=633\ nm$

Hence, The wavelength of the light is 633 nm.

4 0

3 years ago

Place any object (textbook, pen, or eraser) on a floor what happens then

Levart [38]

Answer:

The force of gravity on earth, no matter the object is approximately 9.8 m/ s2 . The reason the crumpled paper hits the ground first is because of air resistance. A crumpled piece of paper has less surface area than an piece of paper that is not crumpled. More surface area means more air resistance.

7 0

2 years ago

A force of 30 N is applied tangentially to the rim of a solid disk of radius 0.10 m. The disk rotates about an axis through its

den301095 [7]

Answer:

m = 4.0 Kg

Explanation:

Using an analogy with the Newton's 2nd law for point masses, for rigid bodies, the external net torque on a rigid body, is equal to its rotational inertia (I), times the angular acceleration (α) of the body, as follows:

$\tau_{ext} = I* \alpha (1)$

Since the magnitude of the torque is the product of the value of the force times the perpendicular distance between the line of action of the force and the axis of rotation, and the force is tangential to the rim of the disk, we can write the following expression:

$\tau = F*r*sin 90 = F*r (2)$