All categories

2 years ago

Which type of rock can only form below earths surface?

Physics

2 answers:

Inessa [10]2 years ago

7 0

Answer: Igneous it forms because of magma but magma is under the earths surface so its Igneous

Explanation:

Degger [83]2 years ago

7 0

Answer:

its metamorphic.

Explanation:

You might be interested in

Calculate the rate of heat conduction through a layer of still air that is 1 mm thick, with an area of 1 m, for a temperature of

max2010maxim [7]

Answer:

The rate of heat conduction through the layer of still air is 517.4 W

Explanation:

Given:

Thickness of the still air layer (L) = 1 mm

Area of the still air = 1 m

Temperature of the still air ( T) = 20°C

Thermal conductivity of still air (K) at 20°C = 25.87mW/mK

Rate of heat conduction (Q) = ?

To determine the rate of heat conduction through the still air, we apply the formula below.

$Q =\frac{KA(\delta T)}{L}$

$Q =\frac{25.87*1*20}{1}$

Q = 517.4 W

Therefore, the rate of heat conduction through the layer of still air is 517.4 W

6 0

3 years ago

Read 2 more answers

Most paper does not reflect light very well because its surface is somewhat rough.<br><br> T or F

Sloan [31]

I think the correct answer is true. Most paper does not reflect light very well because its surface is somewhat rough. Light only reflects to surfaces which has a smooth texture or have a uniform texture on the surface. Hope this answers the question. Have a nice day.

3 0

3 years ago

Read 2 more answers

Have an electrical charge of +1, while

Scrat [10]

Answer:

Explanation:

Protons have a positive electrical charge of +1,

Electrons have a negative charge of -1,

Neutrons have a neutral charge of about 0.

4 0

3 years ago

Determine the final temperature of a gold nugget (mass = 376 g) that starts at 398 K and loses 4.85 kJ of heat to a snowbank whe

m_a_m_a [10]

Answer: Final temperature of a gold nugget will be 297 K

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$q=m\times c\times (T_{final}-T_{initial})$

q = heat released = -4.85 kJ = -4850 J

m = mass of metal = 376 g

$T_{final}$ = final temperature of metal = ?

$T_{initial}$ = initial temperature of metal = 398 K

c = specific heat of metal =

$-4850=376\times 0.128\times (T_{final}-398)$

$(T_{final}-398)=-101$

$(T_{final}=297K$

Thus the final temperature of a gold nugget will be 297 K

6 0

3 years ago

Suppose a clay model of a koala bear has a mass of 0.205 kg and slides on ice at a speed of 0.720 m/s. It runs into another clay

Westkost [7]

Answer:

Final velocity, v = 0.28 m/s

Explanation:

Given that,

Mass of the model, $m_1=0.205\ kg$

Speed of the model, $u_1=0.72\ m/s$

Mass of another model, $m_2=0.32\ kg$

Initial speed of another model, $u_2=0$

To find,

Final velocity

Solution,

Let V is the final velocity. As both being soft clay, they naturally stick together. It is a case of inelastic collision. Using the conservation of linear momentum to find it as :

$m_1u_1+m_2u_2=(m_1+m_2)V$

$V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}$

$V=\dfrac{0.205\times 0.72+0.32\times 0}{(0.205+0.32)}$

V = 0.28 m/s

So, their final velocity is 0.28 m/s. Hence, this is the required solution.

6 0

3 years ago