Answer: (A) vertical asymptote: x = 2, horizontal asymptote: y = 1
<u>Step-by-step explanation:</u>

<u>Vertical Asymptote</u> is the restriction on the x-value. The denominator cannot be zero, so x - 2 ≠ 0 ⇒ x ≠ 2
The restricted value on x is when x = 2 <em>which is the vertical asymptote</em>
<u>Horizontal Asymptote</u> (H.A.) is the restriction on the y-value. This is a comparison of the numerator (n) and denominator (m). There are 3 rules that will help you:
- n > m No H.A. (use long division to find slant asymptote)
- n = m H.A. is the coefficient of n divided by coefficient of m
- n < m H.A. is 0
In the given problem, n < m so y = 0, however there is also a vertical shift of up 1 so the H.A. also shifts up. This results in H.A. of y = 1
Answer:
its -0.4, are those rlly the options? if they are jus round up and do -1
The sand makes up a rectangular prism of dimensions 8' by 10' by 0.5'.
The volume of sand is then V = L*W*H, or V = (10')(8')(0.5') = 40 cubic ft.
Answer:
The actual tower would be 45 ft wide.
Step-by-step explanation:
In order to find the width, we need to determine the scale factor. We can do that by dividing the actual height by the model height.
60ft:24in = 15ft:6in = 2.5ft:1in
Now we use that scale factor to determine the width. Multiply the scale factor by the width of the model.
18 inches * 2.5ft/in = 45 feet