1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Oksi-84 [34.3K]
3 years ago
5

Suppose the Helmholtz coil in this experiment is arranged to produce a magnetic field that points east. The current through the

coils is 11.5 mA. With the current off, the red needle of the compass points at zero degrees on the compass' bezel. At what angle will the compass needle rotate through when current is turned on and left on for a several seconds? Assume the horizontal component of the Earth's magnetic field is 0.24 G and recall the constant k = 17.0 G/A.

Physics
1 answer:
Irina18 [472]3 years ago
7 0

Answer:

∅ = 39.2°

Explanation:

B= B<em>horizontal × </em>tan ∅

11.5×10⁻³ × 17 = 0.24 tan ∅

tan ∅ = (11.5×10⁻³× 17) ÷ 0.24

tan ∅ = 0.8146

∅ = tan⁻¹ 0.8146

∅ = 39.2°

You might be interested in
during convection, hot material _____ (expands &amp; sinks, cools &amp; rises, expands &amp; rises, deflates &amp; rises) then m
Lady bird [3.3K]

Answer:

During convection, hot material expands & rises then moves to the side and cools & sinks. this circular pattern is called a convection current.

Explanation:

Convection is one of the three methods of transfer of heat. It occurs only in fluids (liquids or gases).

Convection occurs when there is a source of heat that heats a fluid, such as in a boiling pot of water. The water which is on the bottom of the pot becomes warmer before than the water at the top (because it is closer to the flame), and so it becomes less dense: for this reason, it expands and it becomes rising. On the contrary, the water on top is colder, so it is more dense and starts sinking, replacing the warmer water. As the new part of water gets warmer, it starts rising, and so the process is continuously repeated. This circular current is called convection current.

4 0
3 years ago
Read 2 more answers
A concert loudspeaker suspended high off the ground emits 34 W of sound power. A small microphone with a 1.0 cm2 area is 44 m fr
rjkz [21]

Answer:

<u>Part A</u>

I = 1.4 mW/m²  

<u>Part B</u>

β = 91.46 dB

Explanation:

<u>Part A</u>

Sound intensity is the power per unit area of sound waves in a direction perpendicular to that area. Sound intensity is also called acoustic intensity.

For a spherical sound wave, the sound intensity is given by;

                                            I = \frac{P}{A}

                                            I = \frac{P}{4\pi r^{2}}

Where;

P is the source of power in watts (W)

I is the intensity of the sound in watt per square meter (W/m2)

r is the distance r away

Given:

P = 34 W,

A = 1.0 cm²

r = 44 m

The sound intensity at the position of the microphone is calculated to be;

                                     I = \frac{34}{4\pi (44)^{2}}

                                     I = \frac{34}{4\pi (44)^{2}}

                                     I = 0.0013975 W/m²

                                 ≈  I = 0.0014 W/m² = 1.4 × 10⁻³ W/m²

                                     I = 1.4 mW/m²

The sound intensity at the position of the microphone is 1.4 mW/m².

<u>Part B</u>

Sound intensity level or acoustic intensity level is the level of the intensity of a sound relative to a reference value.  It is a a logarithmic quantity. It is denoted by β and expressed in nepers, bels, or decibels.

Sound intensity level is calculated as;  

                                    β = 10log_{10}\frac{I}{I_{0}}  dB

Where,

β is the Sound intensity level in decibels (dB)

I is the sound intensity;

I₀ is the reference sound intensity;

By pluging-in, I₀ is 1.0 × 10⁻¹² W/m²

           ∴        β = 10log_{10}\frac{1.4 * 10^{-3} W/m^{2}}{1.0 * 10^{-12} W/m^{2}}

                      β = 10log_{10} (1.4 * 10^{9})

                      β = 91.46 dB

The sound intensity level at the position of the microphone is 91.46 dB.                

4 0
3 years ago
A CFL bulb has an efficiency of 8.9% and a power of 22 W. How much light energy does the lightbulb produce in 1 second
hjlf
The power that the light is able to utilize out of the supply is only 0.089 of the given.
                           Power utilized = (0.089)(22 W)
                                                  = 1.958 W
                                                  = 1.958 J/s
The energy required in this item is the product of the power utilized and the time. That is,
                           Energy = (1.958 J/s)(1 s) = 1.958 J
Thus, the light energy that the bulb is able to produce is approximately 1.958 J. 
6 0
3 years ago
Read 2 more answers
A sports car accelerates from 0 to 25 meters per second in 4 seconds. What is its acceleration?
WITCHER [35]

Answer:

6.25 ms²

Explanation:

..................

3 0
2 years ago
What’s the equalibrium rule?
ale4655 [162]
The vector sum of forces acting on a non-accelerating object equals zero.
equation form: ΣF = 0
4 0
3 years ago
Read 2 more answers
Other questions:
  • In the lens equation, the variable do represents the distance of the object from the ________.
    11·2 answers
  • What is the function of an electrical motor in terms of electric power and motion?
    12·1 answer
  • A wave which needs a medium (solid, liquid, gas) in order to propagate itself.
    8·2 answers
  • Determine the frequency of light whose wavelength is 4.257 x 10-7 cm
    13·1 answer
  • Find the magnitude of vector A = i - 2j + 3k O V14 10 O4
    15·1 answer
  • Which of the following statement is false
    15·2 answers
  • A _ spreads light into its own individual colors.
    14·2 answers
  • What is the fate of solar radiation that reaches the earth?
    5·1 answer
  • An object of mass m 1 moving with speed v collides with another object of mass m 2 at rest and stick to it. Find the impulse to
    5·1 answer
  • 5. A wire, resistance 23.6 carries a current. 5.9 A. What is the
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!