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Oksi-84 [34.3K]
3 years ago
5

Suppose the Helmholtz coil in this experiment is arranged to produce a magnetic field that points east. The current through the

coils is 11.5 mA. With the current off, the red needle of the compass points at zero degrees on the compass' bezel. At what angle will the compass needle rotate through when current is turned on and left on for a several seconds? Assume the horizontal component of the Earth's magnetic field is 0.24 G and recall the constant k = 17.0 G/A.

Physics
1 answer:
Irina18 [472]3 years ago
7 0

Answer:

∅ = 39.2°

Explanation:

B= B<em>horizontal × </em>tan ∅

11.5×10⁻³ × 17 = 0.24 tan ∅

tan ∅ = (11.5×10⁻³× 17) ÷ 0.24

tan ∅ = 0.8146

∅ = tan⁻¹ 0.8146

∅ = 39.2°

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Answer:

Explanation:

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A 1.50-kg iron horseshoe initially at 550°C is dropped into a bucket containing 25.0 kg of water at 20.0°C. What is the final te
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Answer:

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Explanation:

Given:-

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- The initial temperature of horseshoe, Ti_h = 550°C

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- The mass of water, M = 25 kg

- The initial temperature of water, Ti_w = 20°C

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- The interaction of horseshoe and water at their respective initial temperatures will obey the Zeroth and First Law of thermodynamics. The horseshoe at higher temperature comes in thermal equilibrium with the water at lower temperature. We denote the equilibrium temperature as (Te) and apply the First Law of thermodynamics on the system:

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                             Te = [ m*ci*( Ti_h ) + M*cw*( Ti_w ) ] / [ m*ci + M*cw ]

- Plug in the values and evaluate (Te):

                             Te = [1.5*448*550 + 25*4186*20 ] / [ 1.5*448 + 25*4186 ]

                             Te = 2462600 / 105322

                             Te =  23.4 °C    

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