Suppose the Helmholtz coil in this experiment is arranged to produce a magnetic field that points east. The current through the
coils is 11.5 mA. With the current off, the red needle of the compass points at zero degrees on the compass' bezel. At what angle will the compass needle rotate through when current is turned on and left on for a several seconds? Assume the horizontal component of the Earth's magnetic field is 0.24 G and recall the constant k = 17.0 G/A.
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Answer:
x = 0.327 m
Explanation:
Block 2 of mass 1.00 kg is at rest
spring constant = 200 N/m
Block 1 of mass 2 kg moving at 4 m/s
m₁ v₁ = (m₁ + m₂)V
2 x 4 = (2 + 1) V
V = 2.67 m/s
loss of kinetic energy = gain elastic potential energy
x = 0.327 m
hence, the spring compressed distance is equal to x = 0.327 m