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GaryK [48]
4 years ago
8

A floor system has W24 x 55 sections spaced 8’-0"" o.c. supporting a floor dead load of 50 psf and a live load of 80 psf. Determ

ine the governing load. Show all work.
Engineering
1 answer:
galben [10]4 years ago
4 0

Answer:

Load sup[port by beam is 1040 lb/ft

Explanation:

Given data:

dead load of floor is 50 psf

live load of floor is 80 psf

load per meter can be determined as

Load/mt length = load intensity × effective width

total load  = deal load + live load

                  = 50 + 80 = 130 psf

load /mt length =  130 × 8

                         = 1040 p/ft = 1.04 k /ft

hence load sup[port by beam is 1040 lb/ft

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One-dimensional, steady-state conduction with uniform internal energy generation occurs in a plane wall with a thickness of 50 m
uysha [10]

Answer: please help me tooo

Explanation:

4 0
3 years ago
This style is closest to the cuisine enjoyed by French royalty and nobility.
liraira [26]

Answer: С

. Haute cuisine

Explanation:

Haute Cuisine is typically associated with higher level establishments due to the time and cost it takes to prepare as it involves meticulous preparation and usually uses exotic ingredients which make it quite expensive.

It is therefore no wonder that it came to be in order to feed the 'privileged' people in France being the French Royals and Nobles in the 17th century. It differed from normal cooking at the time by using exotic ingredients such as tongue and caviar and as such, gave those who ate it a feeling of superiority.  

8 0
3 years ago
Air is drawn from the atmosphere into a turbomachine. At the exit, conditions are 500 kPa (gage) and 130oC. The exit speed is 10
finlep [7]

Answer:

P=- 88.41 KW

Negative sign indicates that power is given to the system.

Explanation:

Given that

P₂=500 KPa

T₂=130°C

V₂=100 m/s

mass flow rate ,m= 0.8 kg/s

Lets take inlet condition for air

T₁=25°C

P₁=100 KPa

V₁=0 m/s

We know that

Heat capacity for air Cp=1.005 KJ/kg.k

We know that for air change in enthalpy only depends only on temperature

Now from first law for open system

h_1+\dfrac{V_1^2}{2000}=h_2+\dfrac{V_2^2}{2000}+W

1.005\times 298+\dfrac{0^2}{2000}=1.005\times 403+\dfrac{100^2}{2000}+W

W=1.005\times 298-1.005\times 403-\dfrac{100^2}{2000}

W=-110.52 KJ/kg

Shaft power P = m .W

P = -110.52 x 0.8

P=- 88.41 KW

Negative sign indicates that power is given to the system.

 

3 0
4 years ago
Anything that is made to meet a need or desire is?
slavikrds [6]

Answer:

I think it is process or technology

7 0
3 years ago
Read 2 more answers
An uncharged capacitor and a resistor are connected in series to a source of voltage. If the voltage = 7.41 Volts, C = 11.5 µFar
Musya8 [376]

Answer:

a) RC = 1.03 mseg.

b) Qmax = CV = 85.2 μC

c) Q = 53.9 μC

Explanation:

a) In a RC circuit, during the transient period, the capacitor charges exponentially (starting from 0 due to the voltage in the capacitor can´t change instantaneously) with time, being the exponent -t/RC.

This product RC, which defines the rate at which the capacitor charges, is called the time constant of the circuit.

In this case , it can be calculated as follows:

ζ = R C = 89.4 Ω . 11.5 μF = 1.03 mseg.

b) As the charge begins to build up the capacitor plates, a voltage establishes between plates, that opposes to the battery voltage. When this voltage is equal to the battery one, the capacitor reaches to the maximum charge, which is, by definition, as follows:

Q = C V = 11.5 μF . 7.41 V = 85.2 μC

c) During the charging process, the charge increases following this equation:

Q = CV (1 - e⁻t/RC)

When t = RC, the expression for Q is as follows:

Q = CV ( 1- e⁻¹) = 0.63 x CV = 53.9 μC

6 0
4 years ago
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