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3 years ago

15

A metal bar weighs 8.15 ounces. 93 percent of the bar is silver. How many ounces of silver are in the bar? ( round to the neares

t thousandth)

2 answers:

mestny [16]3 years ago

6 0

Answer:

7.6 ouncees of silver

HOPE IT HELPS!

Step-by-step explanation:

Ymorist [56]3 years ago

3 0

8.15*0.93 = 7.580 Because 93% = 0.93

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Debbie wants to decorate 3 lampshade. The diameter of the top of each lampshade is 8 inches and the diameter of the bottom is 12

user100 [1]

156 pi or about 490.08845396 inches

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3 years ago

3.5x - 11 = 20.5 what does x equal?

stepan [7]

Answer:

x=9

Step-by-step explanation:

3.5x - 11 = 20.5

Add 11 to each side

3.5x - 11+11 = 20.5+11

3.5x = 31.5

Divide each side by 3.5x

3.5x/3.5 = 31.5/3.5

x =9

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3 years ago

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Leokris [45]

Answer:

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Step-by-step explanation:

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3 0

2 years ago

Help with this question Asap!! I need all the help I can get!

tankabanditka [31]

Answer:

$\large{YES}\ \dfrac{BC}{YZ}=\dfrac{AC}{XY}=\dfrac{AB}{XZ}=\dfrac{2}{1}\\\\\text{and}\ \angle B\cong\angle Z,\ \angle C\cong\angle Y,\ \angle A\cong\angle X$

Step-by-step explanation:

$BC\to ZY\\AB\to XZ\\AC\to XY\\\angle A\to\angle X\\\angle B\to\angle Z\\\angle C\to\angle Y$

$\text{We have:}\\\\\triangle ABC:\ AB=20,\ BC=12,\ AC=18\\\triangle XZY:\ XZ=10,\ YZ=6,\ XY=9\\\\\text{check the ratio:}\\\\\dfrac{AB}{XZ}=\dfrac{20}{10}=2\\\\\dfrac{BC}{YZ}=\dfrac{12}{6}=2\\\\\dfrac{AC}{XY}=\dfrac{18}{9}=2\\\\\text{CORRECT :)}\\\\\angle B\cong\angle Z,\ \angle C\cong\angle Y\\\\\text{We know that: The sum of the acute angles in a right triangle is}\ 90^o.\\\\m\angle B+m\angle A=90^o\ \text{and}\ m\angle Z+m\angle X=90^o$

$\text{We know}\ m\angle B=m\angle Z\to \ m\angle A=m\angle X.\\\text{therefore}\ \angle A\cong\angle X$

5 0

3 years ago

Speeding: On a stretch of Interstate-89, car speed is a normally distributed variable with a mean of 69.1 mph and a standard dev

Alborosie

Answer: 11.9%

Step-by-step explanation:

Given : On a stretch of Interstate-89, car speed is a normally distributed variable with $\mu=69.1$ mph and $\sigma=3.3$ mph.

Let x be a random variable that represents the car speed.

Since , $z=\dfrac{x-\mu}{\sigma}$

z-score corresponds x = 73 , $z=\dfrac{73-69.1}{3.3}\approx1.18$

Required probability :

$\text{P-value }: P(x>73)=P(z>1.18)\\\\=1-P(z$

[using z-value table.]

Hence, the approximate percentage of cars are traveling faster than you = 11.9%

8 0

3 years ago