we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y/x=k or y=kx
so
That means it's the equation of a line passing through the origin.
case a) and case d) are discarded because the line does not pass through the origin
<u>case b) we have</u>
for x=2 y=4
y/x=k-------> 4/2=2------> k=2
y=2x-------> in this case the value of y is two times the value of x
<u>case c) we have</u>
for x=4 y=2
y/x=k-------> 2/4=1/2------> k=(1/2)
y=(1/2)x-------> in this case the value of y is one-half of the value of x
therefore
the solution is the case c) see the attached figure
Answer:
slope = -
Step-by-step explanation:
given f(4) = 6 and f(- 2) = 8 , then 2 points on the line are
(4, 6 ) and (- 2, 8 )
calculate slope m using the slope formula
m =
with (x₁, y₁ ) = (4, 6 ) and (x₂, y₂ ) = (- 2, 8 )
m = = = -
<h3>
<u>Answer:</u></h3>
<h3>
<u>Step-by-step explanation:</u></h3>
Here , two circles are given which are concentric. The radius of larger circle is 10cm and that of smaller circle is 4cm . And we need to find thelarea of shaded region.
From the figure it's clear that the area of shaded region will be the difference of areas of two circles.
Let the,
- Radius of smaller circle be r .
- Radius of smaller circle be r .
- Area of shaded region be
<h3>
<u>Hence </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> the</u><u> </u><u>shaded </u><u>region</u><u> is</u><u> </u><u>2</u><u>6</u><u>4</u><u> </u><u>cm²</u><u>.</u></h3>
Answer:
0.003981 . . . . moles per liter
Step-by-step explanation:
The concentration of H+ ions in the acid will be ...
10^(-2.4) ≈ 0.003981 . . . . moles per liter
The concentration of H+ ions in the base will be ...
10^-11.2 ≈ 0.000 000 000 006310 . . . . moles per liter
To a few decimal places, the difference is ...
0.003981 . . . . moles per liter
_____
The two numbers differ by about 9 orders of magnitude, so the value of the difference between the larger and the smaller is essentially the value of the larger number. The smaller one, by comparison, can be considered to be zero (for subtraction purposes).