Answer:
H_2O + 2CrO_4^2- + 3SO_3^2- -> 3SO_3^2- + 2CrO_2^- + 2OH^-
Explanation:
Reduction half reaction
2H_2O + CrO_4^2- + 3e -> CrO_2^- + 4OH^-
Oxidation half reaction
2OH^- + SO_3^2- -> SO_4^2- + H_2O + 2e
Balanced overall equation
H_2O + 2CrO_4^2- + 3SO_3^2- -> 3SO_3^2- + 2CrO_2^- + 2OH^-
It bonds atoms together to create molecules
Answer:
single orbital, s sub level.
three orbitals, p sub level
5 orbitals , d sub level
seven orbital , f sub level
Answer:
* 
* 
* 
Explanation:
Hello,
In this case, for the mole fraction of methanol we use the formula:
Thus, we compute the moles of both water (molar mass 18 g/mol) and methanol (molar mass 32 g/mol):
Hence, mole fraction is:
Next, mass percent is:
And the molality, considering the mass of water in kg (0.185 kg):
Regards.
Answer:
option d oxygen nitrogen and carbon dioxide can be classified elements hope ur help
