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Zepler [3.9K]
2 years ago
5

Where are most organisms that live in the ocean found ? why ?

Chemistry
1 answer:
masya89 [10]2 years ago
3 0

Most ocean life is found in coastal habitats. Coastal habitats have more light than the deep ocean resulting in a higher concentration of organisms. Plant species are especially abundant in coastal habitats.

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James is looking at a parallel circuit plan for lighting. There is a battery providing the power. There are switches labeled A,B
Nadya [2.5K]
The answer is D because for light 3 to function switch d does not  have to turn on
7 0
2 years ago
Read 2 more answers
11.
Lostsunrise [7]

Answer:

(1) -12 Kcal/mol

Explanation:

Our answer options for this question are:

(1) -12 Kcal/mol

(2) -13 Kcal/mol

(3) -15 Kcal/mol

(4) -16 Kcal/mol

With this in mind, we can start with the chemical reaction (Figure 1). In this reaction, <u>two bonds are broken</u>, a C-H and a Br-Br. Additionally, a C-Br and a H-Br are <u>formed</u>.

If we want to calculate the enthalpy value, we can use the equation:

<u>ΔH=ΔHbonds broken-ΔHbonds formed</u>

If we use the energy values reported, its possible to calculate the energy for each set of bonds:

<u>ΔHbonds broken</u>

<u />

C-H = 94.5 Kcal/mol

Br-Br = 51.5 Kcal/mol

Therefore:

105 Kcal/mol + 53.5 Kcal/mol = 146 Kcal/mol

<u>ΔHbonds formed</u>

C-Br = 70.5 Kcal/mol

H-Br = 87.5 Kcal/mol

Therefore:

70.5 Kcal/mol + 87.5 Kcal/mol = 158 Kcal/mol

<u>ΔH of reaction</u>

<u />

ΔH=ΔHbonds broken-ΔHbonds formed=(146-158) Kcal/mol = -12 Kcal/mol

I hope it helps!

<u />

6 0
3 years ago
Please help
KonstantinChe [14]

Answer:  There are 0.5 grams of barium sulfate are present in 250 of 2.0 M BaSO_{4} solution.

Explanation:

Given: Molarity of solution = 2.0 M

Volume of solution = 250 mL

Convert mL int L as follows.

1 mL = 0.001 L\\250 mL = 250 mL \times \frac{0.001 L}{1 mL}\\= 0.25 L

Molarity is the number of moles of solute present in liter of solution. Hence, molarity of the given BaSO_{4} solution is as follows.

Molarity = \frac{mass}{Volume (in L)}\\2.0 M = \frac{mass}{0.25 L}\\mass = 0.5 g

Thus, we can conclude that there are 0.5 grams of barium sulfate are present in 250 of 2.0 M BaSO_{4} solution.

7 0
3 years ago
Is the cyanide ion a strong or weak base?
11111nata11111 [884]
It's a weak base bacause H C N is weak
4 0
2 years ago
A 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C. If the final temperature of water is 42.0 °C, what
ludmilkaskok [199]

The initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C

<h3>How to calculate temperature?</h3>

The initial temperature of the copper metal can be calculated using the following formula on calorimetry:

Q = mc∆T

mc∆T (water) = - mc∆T (metal)

Where;

  • m = mass
  • c = specific heat capacity
  • ∆T = change in temperature

According to this question, a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C. If the final temperature of water is 42.0 °C, the initial temperature of the copper is as follows:

400 × 4.18 × (42°C - 24°C) = 240 × 0.39 × (T - 24°C)

30,096 = 93.6T - 2246.4

93.6T = 32342.4

T = 345.5°C

Therefore, the initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C.

Learn more about temperature at: brainly.com/question/15267055

8 0
1 year ago
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