<em>n</em> = 15. A Bohr orbit with <em>n</em> = 15 comes closest to having a 24 nm diameter
.
The formula for the radius <em>r</em> of the <em>n</em>th orbital of a hydrogen atom is
<em>r</em> = <em>n</em>^2·<em>a</em>
where
<em>a</em> = the Bohr radius = 0.0529 nm
We can solve this equation to get
<em>n</em> = √ (<em>r</em>/<em>a</em>)
If <em>d</em> = 24 nm, <em>r</em> = 12 nm.
∴ <em>n</em> = √(12 nm/0.0529 nm) = √227 = 15.1
<em>n</em> must be an integer, so <em>n</em> = 15.
Answer:
C
Explanation:
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Answer:
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