Answer:
112.92 s.
Explanation:
Let M₁ be the molar mass of N₂O
Let t₁ be the time taken for N₂O to effuse.
Let M₂ be the molar mass of I₂
Let t₂ be the time taken for I₂ to effuse.
Molar mass (M₁) of N₂O = (14×2) + 16 = 28 + 16 = 44 g/mol
Time (t₁) of effusion of N₂O = 47 s
Molar mass (M₂) of I₂ = 127 × 2 = 254 g/mol
Time (t₂ ) of effusion of I₂ =?
The time take for the same amount of I₂ to effuse can be obtained as follow:
t₂/t₁ = √(M₂/M₁)
t₂/47 = √(254 / 44)
Cross multiply
t₂ = 47 × √(254 / 44)
t₂ = 112.92 s
Therefore, it will take 112.92 s for the same amount of I₂ to effuse.
Answer:
The seafloor
Explanation:
the bottom of the ocean, aka the sea floor.
usually made from sand
Idk but it is probably fast
Mg(NO3)2 ➡️ Mg2+ + 2 NO3-
（32.0g Mg(NO3)2) / (148.3g Mg(NO3)2/mol)* (2 mol NO3- / 1 mol Mg(NO3)2) / (0.425 L) = 1.02 mol/ L NO3-
