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podryga [215]
3 years ago
9

How many ounces are in a 2-liter of soda? Just out of curiousity?

Chemistry
1 answer:
tamaranim1 [39]3 years ago
6 0
There are 67.6 ounces in a 2-liter soda.
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Write a chemical equation for the following decomposition reaction.
Aneli [31]
<span>the chemical equation will be Ni(OH)2(s)------>heat---> NiO(s) + H2O(g)
</span><span>we know that the heat supplied to decompose the compound.In the result the product H2O is assumed to be in the vapor state so that is gas.

hope it helps
</span>
7 0
3 years ago
When 40 grams of ammonium nitrate explode 14 grams of nitrogen and 8 grams of oxygen form. How many grams of water form
DerKrebs [107]

Answer:

18 grams of water

Explanation:

The Balance Chemical Reaction is as follow,

                     2 NH₄NO₃    →    2 N₂  +  O₂  +  4 H₂O

According to Equation,

                     160 g (2 moles) NH₄NO₃ produces  =  72 g (4 moles) of H₂O

So,

                     40 g of NH₄NO₃ will produce  =  X g of H₂O

Solving for X,

                     X =  (40 g × 72 g) ÷ 160 g

                     X  =  18 g of H₂O

<em>Hope This Helps!</em>

4 0
2 years ago
When 0.620 gMngMn is combined with enough hydrochloric acid to make 100.0 mLmL of solution in a coffee-cup calorimeter, all of t
OleMash [197]

Answer:

The enthalpy change during the reaction is -199. kJ/mol.

Explanation:

Mn(s)+2HCl(aq)\rightarrow  MnCl_2(aq)+H_2(g)

Mass of solution = m

Volume of solution = 100.0 mL

Density of solution = d = 1.00 g/mL

m=1.00 g/mL\times 100.0 mL = 100 g

First we have to calculate the heat gained by the solution in coffee-cup calorimeter.

q=m\times c\times (T_{final}-T_{initial})

where,

m = mass of solution = 100 g

q = heat gained = ?

c = specific heat = 4.18 J/^oC

T_{final} = final temperature = 23.1^oC

T_{initial} = initial temperature = 28.9^oC

Now put all the given values in the above formula, we get:

q=100 g \times 4.18 J/^oC\times (28.9-23.1)^oC

q=2,242.4 J=2.242 kJ

Now we have to calculate the enthalpy change during the reaction.

\Delta H=-\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat gained = 2.242 kJ

n = number of moles fructose = \frac{\text{Mass of manganese}}{\text{Molar mass of manganese}}=\frac{0.620 g}{54.94 g/mol}=0.0113 mol

\Delta H=-\frac{2.242 kJ}{0.0113 mol }=-199. kJ/mol

Therefore, the enthalpy change during the reaction is -199. kJ/mol.

8 0
3 years ago
Lons can have a positive or negative charge.<br> True or false
fiasKO [112]
Yes, it is true that ions can have a positive or negative charge.
7 0
3 years ago
Read 2 more answers
What compound/element is this? <br><br> (Easy)
Karo-lina-s [1.5K]

Answer:

C₃H₆ propene

Explanation:

Find the chemical formula by adding all the carbon and then all the hydrogen together.

5 0
3 years ago
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