Answer:
The agent causing the pneumonia, where bluish-green pus was found, is most likely Pseudomonas aeruginosa.
Explanation:
Pseudomona aeuriginosa is a gram-negative bacteria that is one of the main causes of hospital-acquired infections, including pneumonias in mechanically ventilated patients.
One of the characteristics of P. aeuriginosa is the formation of a bluish-green pus, since it has the capacity to form cyanide-based blue pigment upon contact with the organic tissues it infects. This is the reason why previously P. aeruginosa was called a pyocyanic bacillus.
<em> The other options are not correct because the only bacterium that produces blue-green pus is P. aeruginosa.</em>
If the farmer were to breed both of the two different types of cattle he would have a hybrid type of new cattle with both traits :)
Codons that code for the same amino acid are termed synonyms, Silent mutations are base substitutions that result in no change of the amino acid or amino acid functionality when the altered messenger RNA (mRNA) is translated.
Photosynthesis occurs only in the light while cellular respiration occurs in both the dark and the light. Photosynthesis is the process used by plants, algae and certain bacteria to harness energy from sunlight into chemical energy. The process takes in carbon dioxide produced by all breathing organisms and reintroduces oxygen into the atmosphere. Cellular respiration is a set of metabolic reactions and processes that take place in the cells of organisms to convert biochemical energy from nutrients into ATP, and the release waste products.
Answer:
1. How did the tidal wave affect the predicted frequencies of the alleles in the population?
No changes
2. What is the frequency of the recessive allele?
q= 0.6
Explanation:
If we assume that all individuals were equally likely to be wiped out, that means the frequency/ratio of the gene and genotype of the population will not change. The tidal wave killing 100 out of 200, so it simply makes the population become half of it used to be.
If the population at equilibrium, we can use the Hardy-Weinberg formula to find out the expected frequency of the dominant and recessive alleles. There are 36 homozygous recessives out of 100, so the frequency of the recessive allele will be:
q^2 = 36/100
q= √36/100= 6/10= 0.6