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3 years ago

A. explain in detail why dissolved oxygen in seawater can be used as an indicator of primary production.

2 answers:

wel3 years ago

4 0

"Dissolved oxygen in seawater is used as an indicator of primary production (as its surrogate, so to speak) because the amount of molecular oxygen produced during photosynthesis is directly proportional to the amount of carbon fixed during photosynthesis, and determining the amount of dissolved oxygen is much easier to do."

Andrews [41]3 years ago

3 0

Dissolved sea water is used as primary production to kill all the germs in the water

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Which of the statements about half-life are true?

Oksana_A [137]

The statements which are true about half-life are given below:

A radioactive element's half-life stays the same when its temperature changes.
A radioactive element's half-life stays the same when the pressure upon it changes.

Thus, the correct options are B and F.

The half-life of any radioactive element may be defined as the time taken for the radioactivity of a specified isotope to drop to half of its original value.

The above statement is true about the half-life of any radioactive element because the half-life of any substance does not depend on pressure, temperature, and concentration.

Therefore, it is well described above.

To learn more about Half-life, refer to the link:

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2 years ago

What is a thesis statement?

Umnica [9.8K]

A. A statement of purpose

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3 years ago

The biological selection of a particular allele for a trait to be passed to offspring has nothing do with the selection of the a

blagie [28]

Answer:

Explanation:

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3 years ago

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Mila [183]

Answer:

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3 years ago

Example 1: Two different enzymes are able to catalyze the same reaction, A → B. They both have the same Vmax, but differ their K

luda_lava [24]

Answer: (a) = 0.022mmoles/minute; (b) = 0.00022mmoles/minute; (c) = 0.022mmoles/minute

Explanation:

The Michaelis- Menten equation is used to show the relationship between substrate concentration and reaction rate.

The equation is Vo = Vmax[S]/(Km + [S]

where Vo is the initial velocity, Vmax is the maximum velocity, [S] is the substrate concentration, Km is the Michaelis constant.

(a) For enzyme 1; Vo = 0.002mmoles/minute, Vmax = ?, [S] = 0.1mM, Km =1.0mM; making Vmax subject of the formula;

Vmax = Vo * (Km + [S])/ [S]

Vmax = 0.002*(1.0 + 0.1)/ 0.1

Vmax = 0.022mmoles/minute (Vmax for Enzyme 1&2)

(b) Vo = Vmax[S]/(Km + [S]

Vo = 0.022 * 0.1/(10+0.1) = 0.00022mmoles/minute

Vo = 0.022*1000/(1.0+1000) = 0.022mmoles/minute

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3 years ago