Question

Solve for x for 0 ≤ x < 2 π . tanxsinx - tanx = 0

Answer 1

Let's solve this

We need to accept solutions in the given interval 0 ≤ x < 2 pi

tanx * sinx - tanx = 0  First we pull out tanx in front of the bracket and get

=> tanx ( sinx - 1 ) = 0  now we interpret product and get

tanx = 0 or sinx - 1 = 0

When tanx = 0 => angle is x1=0

sinx - 1 = 0 => sinx = 1   When sinx = 1 then angle is x2= pi/2

The solutions are inside given interval 0 ≤ x < 2 pi and we accept it.

The correct answer is (x1, x2) = (0, pi/2)

Good luck!!!