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3 years ago

Which list includes only physical properties

Chemistry

2 answers:

Nikitich [7]3 years ago

4 0

Answer:

Option (B) is correct

Explanation:

Trust

IRINA_888 [86]3 years ago

3 0

The list that include only the physical properties are: BOILING POINTS, CONDUCTIVITY AND COLOUR.

Physical properties are those properties of matter which can be observed and quantified without changing the composition of the material. Examples of physical properties are boiling point, melting points, electrical conductivity, colour, ductility, malleability, odour, density, solubility, polarity, texture, appearance, luster, hardness, etc.

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In volcanic areas, groundwater heated by magma is a source of

crimeas [40]

Answer:I believe it is c.

Explanation:

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3 years ago

One way in which the useful metal copper is produced is by dissolving the mineral azurite, which contains copper(II) carbonate,

kompoz [17]

Answer:

0.0075 M

Explanation:

Mass of copper metal recovered:

$m_o = 95 mg = 95\cdot 10^{-3} g$

Molar mass of copper should be used in this problem in order to convert the mass of copper into moles of copper:

$M_o = 63.546 g/mol$

According to the balanced chemical equation, 1 mole of copper(II) sulfate produces 1 mole of copper metal, this means, when we find the number of moles of copper metal, this will be equivalent to the number of moles of copper(II) sulfate. Dividing the number of moles of copper(II) sulfate by the volume of the solution in liters will yield the molarity needed.

Firstly, the number of moles of copper (and copper(II) sulfate):

$n_o = \frac{m_o}{M_o}$

Given a volume of:

$V = 200 mL = 0.200 L$

We obtain a molarity of:

$c_o = \frac{n_o}{V} = \frac{m_o}{M_o V} = \frac{95\cdot 10^{-3} g}{63.546 g/mol\cdot 0.200 L} = 0.0075 M$

3 0

4 years ago

I need help balancing both equations?

erik [133]

Answer:

6CO2 + 6H2O --> C6H12O6 + 6O2

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Explanation:

The balanced form of both equations

5 0

3 years ago

A hydrated salt is a solid that includes water molecules within its crystal structure. A student heated a 12.10-gram sample of a

sveticcg [70]

Answer : The percent by mass of water the salt contain is, 55.3 %

Explanation : Given,

Mass of hydrated salt = 12.10 g

Mass of salt = 5.41 g

First we have to calculate the mass of water.

Mass of water = Mass of hydrate salt - Mass of salt

Mass of water = 12.10 g - 5.41 g

Mass of water = 6.69 g

Now we have to calculate the percent by mass of water the salt contain.

$\text{Percent by mass of water}=\frac{\text{Mass of water}}{\text{Mass of hydrate salt}}\times 100$

Now put all the given values in this expression, we get:

$\text{Percent by mass of water}=\frac{6.69g}{12.10g}\times 100$

$\text{Percent by mass of water}=55.3\%$

Therefore, the percent by mass of water the salt contain is, 55.3 %

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3 years ago

An ocean trench .

Klio2033 [76]

Answer:

C. Occurs where a plate is moving down.

Explanation:

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Please mark as Brainliest! :)

7 0

4 years ago

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