Answer:
<h3>On a coordinate plane, a cube root function goes through (negative 8, negative 2), has an inflection point at (0, 0), and goes thorugh (8, 2).</h3>
Step-by-step explanation:
![f(x)=\sqrt[3]{x}\\\\f(-8)=\sqrt[3]{-8}=-2\to(-8,\ -2)\\\\f(0)=\sqrt[3]{0}=0\to(0,\ 0)\\\\f(8)=\sqrt[3]{8}=2\to(8,\ 2)\\\\\\\sqrt[3]{a}=b\iff b^3=a\\\\\text{Therefore:}\\\\\sqrt[3]{-8}=-2\ \text{because}\ (-2)^3=-8\\\sqrt[3]0=0\ \text{because}\ 0^3=0\\\sqrt[3]{8}=2\ \text{because}\ 2^3=8](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D%5C%5C%5C%5Cf%28-8%29%3D%5Csqrt%5B3%5D%7B-8%7D%3D-2%5Cto%28-8%2C%5C%20-2%29%5C%5C%5C%5Cf%280%29%3D%5Csqrt%5B3%5D%7B0%7D%3D0%5Cto%280%2C%5C%200%29%5C%5C%5C%5Cf%288%29%3D%5Csqrt%5B3%5D%7B8%7D%3D2%5Cto%288%2C%5C%202%29%5C%5C%5C%5C%5C%5C%5Csqrt%5B3%5D%7Ba%7D%3Db%5Ciff%20b%5E3%3Da%5C%5C%5C%5C%5Ctext%7BTherefore%3A%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B-8%7D%3D-2%5C%20%5Ctext%7Bbecause%7D%5C%20%28-2%29%5E3%3D-8%5C%5C%5Csqrt%5B3%5D0%3D0%5C%20%5Ctext%7Bbecause%7D%5C%200%5E3%3D0%5C%5C%5Csqrt%5B3%5D%7B8%7D%3D2%5C%20%5Ctext%7Bbecause%7D%5C%202%5E3%3D8)
Step-by-step explanation:
b^2-4b+3=0
b²-3x-b+3=0
b(b-3)-1(b-3)=0
(b-3)(b-1)=0
either
b=3 or b=1
.
2n^2 + 7 = -4n + 5
2n²+4n+7-5=0
2n²+4n+2=0
2(n²+2n+1)=0
(n+1)²=0/2
:.n=-1
.
x - 3x^2 = 5+ 2x - x^2
0=5+ 2x - x^2-x +3x^2
0=5+x+2x²
2x²+x+5=0
comparing above equation with ax²+bx +c we get
a=2
b=1
c=5
x={-b±√(b²-4ac)}/2a ={-1±√(1²-4×2×5)}/2×1
={-1±√-39}/2