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2 years ago

6

What is the frequency of a radio wave with a wavelength of 578.0m

1 answer:

Radda [10]2 years ago

4 0

Answer:

0.0017 Hz

Explanation:

the solution is in the photo

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In humans, infections by fungi and protists are usually more difficult to treat than bacteria infections. Suggest an explanation

Basile [38]

<span>Fungal diseases are difficult to treat mainly because they are eukaryotic organisms just like us humans, and therefore have less differences for drugs to target without harming the human body as well. Most antibiotics target e.g. the peptidoglycan layer in the bacterial (a prokaryote) cell wall, which is a safe target since eukaryotic cells do not have equivalent structures. Similarly many differences in metabolic pathways between humans and prokaryotes is often targeted by antibiotics, but metabolism of fungi and humans is much more uniform, and hence it is difficult to exclusively target the fungi only.

HOPE THIS HELPS!

</span>

5 0

3 years ago

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) A children’s liquid cold medicine has a density of 1.23 g/mL. If a child is to take 2.5 tsp in a dose, what is the mass in gra

vekshin1

The relation between density and mass and volume is

$Density=\frac{Mass}{volume}$

the dose required is 2.5 tsp

each tsp contain 5mL

So dose required in mL = 2.5 X 5 = 12.5 mL

the mass will be calculated using following formula

$Mass=DensityXvolume$

$Mass=1.23\frac{g}{mL}X12.5mL= 15.38g$

The mass of dose in grams will be 15.38 g

5 0

3 years ago

Hoochie [10]

a. volume of NO : 41.785 L

b. mass of H2O : 18 g

c. volume of O2 : 9.52 L

<h3>Further explanation</h3>

Given

Reaction

4 NH₃ (g) + 5 O2 (g) → 4 NO (g) + 6 H2O (l)

Required

a. volume of NO

b. mass of H2O

c. volume of O2

Solution

Assume reactants at STP(0 C, 1 atm)

Products at 1000 C (1273 K)and 1 atm

a. mol ratio NO : O2 from equation : 4 : 5, so mo NO :

$\tt \dfrac{4}{5}\times 0.5=0.4$

volume NO at 1273 K and 1 atm

$\tt V=\dfrac{nRT}{P}=\dfrac{0.4\times 0.08206\times 1273}{1}=41.785~L$

b. 15 L NH3 at STP ( 1mol = 22.4 L)

$\tt \dfrac{15}{22.4}=0.67~mol$

mol ratio NH3 : H2O from equation : 4 : 6, so mol H2O :

$\tt \dfrac{6}{4}\times 0.67=1$

mass H2O(MW = 18 g/mol) :

$\tt mass=mol\times MW=1\times 18=18~g$

c. mol NO at 1273 K and 1 atm :

$\tt n=\dfrac{PV}{RT}=\dfrac{1\times 35.5}{0.08206\times 1273}=0.34$

mol ratio of NO : O2 = 4 : 5, so mol O2 :

$\tt \dfrac{5}{4}\times 0.34=0.425$

Volume O2 at STP :

$\tt 0.425\times 22.4=9.52~L$

5 0

3 years ago

To objects (A and B) of the same temperature are in contact with each other? Which statement is true.

denpristay [2]

Que pa’so thosui? Esta bious classa?

5 0

2 years ago

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Describe the basic particle from which all ements are made

maxonik [38]

The answer for this question is: Atoms

7 0

2 years ago

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