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Bas_tet [7]
3 years ago
6

What is the frequency of a radio wave with a wavelength of 578.0m

Chemistry
1 answer:
Radda [10]3 years ago
4 0

Answer:

0.0017 Hz

Explanation:

the solution is in the photo

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Consider the balanced equation for the following reaction:
Bad White [126]

<u>Answer:</u> The theoretical yield of the lithium chlorate is 1054.67 grams

<u>Explanation:</u>

To calculate the mass for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Actual moles of lithium chlorate = 9.45 moles

Molar mass of lithium chlorate = 90.4 g/mol

Putting values in above equation, we get:

9.45mol=\frac{\text{Actual yield of lithium chlorate}}{90.4g/mol}\\\\\text{Actual yield of lithium chlorate}=(9.45mol\times 90.4g/mol)=854.28g

To calculate the theoretical yield of lithium chlorate, we use the equation:

\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100

Actual yield of lithium chlorate = 854.28 g

Percentage yield of lithium chlorate = 81.0 %

Putting values in above equation, we get:

81=\frac{854.28g}{\text{Theoretical yield of lithium chlorate}}\times 100\\\\\text{Theoretical yield of lithium chlorate}=\frac{854.28\times 100}{81}=1054.67g

Hence, the theoretical yield of the lithium chlorate is 1054.67 grams

7 0
2 years ago
Which of the these is a balanced chemical equation? A) CO(g) + O2(g) → CO2(g) B) CO(g) + 2O2(g) → 2CO2(g) C) 2CO(g) + O2(g) → 2C
jenyasd209 [6]
Answer: C.

This is because the atoms on either side of the equation in all the other solutions are not equal. 
6 0
3 years ago
Read 2 more answers
The cells of plant and animals lack nuclei
Masteriza [31]
That is not true 
They both have nuclei or we would not be living now
6 0
2 years ago
Given the unbalanced equation below, answer the following: Calculate the number of liters of 3.00 M lead (II) iodide solution pr
mr_godi [17]

The number of liters of 3.00 M lead (II) iodide : 0.277 L

<h3>Further explanation</h3>

Reaction(balanced)

Pb(NO₃)₂(aq) + 2KI(aq) → 2KNO₃(aq) + PbI₂(s)

moles of KI = 1.66

From the equation, mol ratio of KI : PbI₂ = 2 : 1, so mol PbI₂ :

\tt \dfrac{1}{2}\times 1.66=0.83

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large \boxed {\bold {M ~ = ~ \dfrac {n} {V}}}

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

So the number of liters(V) of 3.00 M lead (II) iodide-PbI₂ (n=0.83, M=3):

\tt V=\dfrac{n}{M}\\\\V=\dfrac{0.83}{3}\\\\V=0.277~L

5 0
3 years ago
How many moles of c2h6o are in a 24.5 gram sample?
andreev551 [17]
0.5326086957 moles ....
5 0
3 years ago
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