The process of converting nitrogen into nitrogen compounds by bacteria is called:

Why do we have rain........................

VladimirAG [237]

Answer:

to watered our source of food

the "PLANTS & TREES"

6 0

2 years ago

Let a represent the red spheres and b represent the blue spheres. write a balanced equation for the equilibrium reaction.

krok68 [10]

I have attached the diagram related to this question.

Answer:
5A₂ + 5B .................> 4A₂B + A₂ + B

Explanation:
1- For the reactants:
We can note that:
i- we have 5 moles of substance A which is diatomic. This means that we have 5A₂
ii- we have 5 moles of substance B which is monoatomic. This means that we have 5B
Based on the above, for the reactants side, we have:
5A₂ + 5B

2- For the products:
We can note that:
i- we have 4 moles of a substance formed from the combination of two moles of substance A with one mole of substance B. This means that we have 4A₂B
ii- we have one mole of substance A that is diatomic. This means that we have A₂
iii- we have one mole of substance B that is monoatomic. This means that we have B
Based on the above, for the products side, we have:
4A₂B + A₂ + B

3- Combining reactants and products parts:
Combining the reactants side (from part 1) with the products side (from part 2), we can find that the initial equation is as follows:
5A₂ + 5B .................> 4A₂B + A₂ + B

4- Balancing the equation:
Taking a look at the initial equation we reached in part 3, we will find that:
Number of moles of substance A in reactants = 2*5 = 10 moles
Number of moles of substance A in products = 2*4 + 2*! = 10 moles
SUBSTANCE A IS BALANCED
Number of moles of substance B in reactants = 5*1 = 5 moles
Number of moles of substance B in products = 4*1 + 1 = 5 moles
SUBSTANCE B IS BALANCED
Based on the above, the final balanced equation is the same as the initial equation reached in part 3:
5A₂ + 5B .................> 4A₂B + A₂ + B

Hope this helps :)

6 0

3 years ago

Write a complete, balanced equation for the following reactions:

lys-0071 [83]

Answer:

Solution given:

c) Magnesium metal plus silver acetate (teachers note:

Balanced chemical equation:

$\boxed{\bold{\green{Mg+AgC_{2}H_{3}O_{2}\rightarrow MgC_{3}H_{3}O_{2}+Ag^{+}}}}$

d) hydrobromic acid plus zinc metal (teachers note:

Balanced chemical equation:

$\boxed{\bold{\green{2HBr+Zn \rightarrow Be_{2}+H_{2}}}}$

6 0

2 years ago

A 455 g piece of bopper tubing is heated to 89.5 C and placed in an insulated vessel containing 159 g of water at 22.8 C. Assumi

postnew [5]

Answer:

The final temperature of the setup = 36.6°C

Explanation:

Let the final temperature of the setup be T

Heat lost by the copper tubing = Heat gained by water and the vessel

Heat lost by the copper tubing = mC ΔT = 455 × 0.387 × (89.5 - T) = (15759.61 - 176.1T) J

Heat gained by water = mC ΔT = 159 × 4.186 × (T - 22.8) = (665.6T - 15175.1) J

Heat gained by vessel = c ΔT = 10 × (T - 22.8) = (10T - 228) J

Heat lost by the copper tubing = Heat gained by water and the vessel

(15759.61 - 176.1T) = (665.6T - 15175.1) + (10T - 228)

851.7 T = 31162.71

T = 36.6°C

7 0

3 years ago

For the reaction ? Ch3oh+? O2 →? Hco2h+? H2o , what is the maximum amount of hco2h (46.0254 g/mol) which could be formed from 6.

saw5 [17]

Answer:- 9.98 grams.

Solution:- The given balanced equation is:

$CH_3OH+O_2\rightarrow HCO_2H+H_2O$

From this equation, there is 1:1 mol ratio between methanol and formic acid. We start with given grams of methanol and convert them to moles. Then using mol ratio the moles of foramic acid are calculated and finally converted to grams on multiplying by it's molar mass.

The calculations could easily be done using dimensional analysis as:

$6.95gCH_3OH(\frac{1molCH_3OH}{32.0419g})(\frac{1molHCO_2H}{1molCH_3OH})(\frac{46.0254gHCO_2H}{1molHCO_2H})$

= $9.98gHCO_2H$

Hence, 9.98 grams of formic acid can be formed from 6.95 grams of methanol.

8 0

3 years ago