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elena-s [515]
3 years ago
12

a block of wood with a mass of 2.33 kg is at rest on a frictionless pole. A .011 kg bullet is fired 722 m/s and is embedded with

the wood. What is the speed of the bullet block system after the collision occurs.
Physics
1 answer:
MrRissso [65]3 years ago
6 0
Some rewards are 2.33 miles in a hour so you have to move in 700 degrees to get the system moving faster soo 700+ 2.33 divide by 3
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A 97.0 kg ice hockey player hits a 0.150 kg puck, giving the puck a velocity of 48.0 m/s. If both are initially at rest and if t
OverLord2011 [107]

Answer:

s₁ = 0.022 m

Explanation:

From the law of conservation of momentum:

m_1u_1 + m_2u_2 = m_1v_1+m_2v_2

where,

m₁ = mass of hockey player = 97 kg

m₂ = mass of puck = 0.15 kg

u₁ = u₂ = initial velocities of puck and player = 0 m/s

v₁ = velocity of player after collision = ?

v₂ = velocity of puck after hitting = 48 m/s

Therefore,

(97\ kg)(0\ m/s)+(0.15\ kg)(0\ m/s)=(97\ kg)(v_1)+(0.15\ kg)(48\ m/s)\\\\v_1 = -\frac{(0.15\ kg)(48\ m/s)}{97\ kg} \\v_1 = - 0.074 m/s

negative sign here shows the opposite direction.

Now, we calculate the time taken by puck to move 14.5 m:

s_2 =v_2t\\\\t = \frac{s_2}{v_2} = \frac{14.5\ m}{48\ m/s} \\\\t =  0.3\ s

Now, the distance covered by the player in this time will be:

s_1 = v_1t\\s_1 = (0.074\ m/s)(0.3\ s)

<u>s₁ = 0.022 m</u>

4 0
3 years ago
A particle is acted on by two torques about the origin: τ→1 has a magnitude of 8 N·m and is directed in the positive direction o
lyudmila [28]

To give solution to the exercise we must use the concepts of Torque, Vector magnitude and vector direction of the forces.

For the given problem we have to

T_i = 8Nm

T_j = -8.9Nm

In this way the torque acting on the particle as a function of distance and time is,

\tau = \frac{dL}{dt} = 8\hat{i}-8.9\hat{j}

The net torque acting on the particle is

\tau_{net} = \sqrt{T_i^2+T_j^2}

\tau_{net} = \sqrt{(8)^2+(-8.9)^2}

\tau_{net} = 11.967Nm

PART B) The direction of the torque is given by,

tan\theta = \frac{y}{x}

\theta = tan^{-1}\frac{y}{x}

\theta = tan^{-1}(\frac{-8.9}{8})

\theta = -48.04\°

Therefore the torque direction is 48.04° below the x axis.

5 0
3 years ago
What is the Ultraviolet Catastrophe?​
Sholpan [36]

The ultraviolet catastrophe was the prediction of late 19th century/early 20th century classical physics that an ideal black body (also blackbody) at thermal equilibrium will emit radiation in all frequency ranges, emitting more energy as the frequency increases.

7 0
3 years ago
Resistance training should be performed every day for maximum conditioning benefits.
marysya [2.9K]

Answer:

The answer is True

7 0
3 years ago
Read 2 more answers
Technician a says multiple discharge ignition system fires the spark plug during each of the engine's four cycle strokes. Techni
patriot [66]

Answer:

Technician B only is correct

Explanation:

Here we have that the multiple discharge ignition system is a system that fires the spark plug multiple times during each power stroke to provide ample spark to complete the ignition. Therefore,  technician A is not correct.

The dual spark plug ignition system is a method if obtaining the ideal combustion and improved fuel consumption than a single spark plug ignition system.

Therefore, only technician B is correct.

7 0
3 years ago
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