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gogolik [260]
3 years ago
6

The kinetic energy of the pendulum bob in figure 15-1 increases the most between locations

Physics
2 answers:
Ket [755]3 years ago
7 0

Answer:A and C

Explanation:

Fudgin [204]3 years ago
3 0

Answer:

 A and C

Explanation:

 Kinetic energy of a body is given by the expression, KE =\frac{1}{2}mv^2, where v is the velocity and m is the mass of body.

 In case of a simple pendulum the maximum velocity is at it's stationary position.

So maximum velocity i at position C, which means maximum kinetic energy is at position A.

The velocity of pendulum reduces as the angle between vertical stationary and current position increases.

 So, velocity at E and A are the minimum, so at A and E the kinetic energy value is minimum.

 Now examining the options given, we will understand the kinetic energy increase is maximum in case of A and C.

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An airplane flies in a loop (a circular path in a vertical plane) of radius 160 m . The pilot's head always points toward the ce
notka56 [123]

Answer:

a) 39.6 m/s b) 4123 N

Explanation:

a) At the top of the loop, all of the forces point downwards (force of gravity and normal force).

Fnet=ma

ma=m(v^2/R) (centripetal acceleration)

mg=m(v^2/R)

m cancels out (this is why pilot feels weightless) so,

g=(v^2/R)

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v=39.6 m/s

b) At the bottom of the loop, the normal force and the force of gravity point in opposite directions. The normal force is the weight felt.

Convert 300 km/hr to m/s

300 km/hr=83.3 m/s

Convert pilot's weight into mass:

760 N = 77.55 kg

Fnet=ma

n-mg=m(v^2/R)

n=(77.55 kg)(((83.3 m/s)^2)/160 m)+(77.55 kg)(9.8 m/s^2)

n=3363.2 N+760 N=4123 N

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What is one common product that uses microwaves
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For a given wave IF frequency doubles the wavelength
motikmotik

Answer:

C is halved

Explanation:

The frequency and the wavelength of a wave are related by the equation:

v=f\lambda

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v is the speed of the wave

f is the frequency

\lambda is the wavelength

From the equation above, we see that for a given wave, if the wave is travelling in the same medium (and so, its speed is not changing), then the frequency and the wavelength are inversely proportional to each other.

Therefore, if the frequency doubles, the wavelength will halve in order to keep the speed constant:

\lambda = \frac{v}{f}\\\lambda' = \frac{v}{f'}=\frac{v}{2f}=\frac{1}{2}(\frac{v}{f})=\frac{\lambda}{2}

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