KE = (1/2)mv^2
m = 10.0 kg
v = 5.00 m/a
KE = (1/2)(10.0)(5.00)^2 = (1/2)(10.0)(25.0) = 125 J
C. 125 J
<u>Answer:</u> The number of atoms of carbon present in given number of moles are 
<u>Explanation:</u>
We are given:
Number of moles of carbon = 
According to mole concept:
1 mole of an element contains
number of atoms.
So,
of carbon will contain =
number of atoms.
Hence, the number of atoms of carbon present in given number of moles are 
Deoxygenated Blood enters and leaves the right side of the heart then Oxygenated blood enters and leaves the left side of the heart