Answer:
I think it is number 4 which is 3.87 v
Answer:
0.25 g of U-235 isotope will left .
Formula used :
where,
N = amount of U-235 left after n-half lives = ?
= Initial amount of the U-235 = 1.00 g
n = number of half lives passed = 2
0.25 g of U-235 isotope will left .
Answer:
b. 1.5 atm.
Explanation:
Hello!
In this case, since the undergoing chemical reaction suggests that two moles of A react with one moles of B to produce two moles of C, for the final pressure we can write:

Now, if we introduce the stoichiometry, and the change in the pressure
we can write:

Nevertheless, since the reaction goes to completion, all A is consumed and there is a leftover of B, and that consumed A is:

Thus, the final pressure is:

Therefore the answer is b. 1.5 atm.
Best regards!
Answer:

Explanation:
<u>Given:</u>
Number of atoms =
atoms
Avogadro's Number =
atom / mol
<u>Required:</u>
Moles = ?
<u>Formula:</u>

<u>Solution:</u>

no. of moles = 1.55 moles
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:

Explanation:
Hello!
In this case, since we are given the formula units (molecules) of copper sulfate, it is possible to compute the moles of this compound via the Avogadro's number:

Now, given the molar mass of copper sulfate which is 159.60 g/mol, the required mass in grams turns out:

Best regards!