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3 years ago

Which describes the sequence of events of the development of the universe?

Chemistry

2 answers:

tatyana61 [14]3 years ago

6 0

Answer:

big bang → expansion and cooling → atom formation → star and galaxy formation → continuation of expansion and cooling

Explanation:

nordsb [41]3 years ago

6 0

Answer:

D: big bang → expansion and cooling → atom formation → star and galaxy formation → continuation of expansion and cooling

Explanation:

i just took the quiz and it was right! :)

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Why does radius increase as you go down a group (hint: think Bohr-Rutherford diagrams)? Why would an increase in radius make it

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Answer:

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3 years ago

Which is not true of the element nitrogen?

insens350 [35]

B is the answer or check it out

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3 years ago

Which of the following is the correct molecule for dinitrogen trisulfide?

Setler79 [48]

Answer:

A. N2S3

yep u r right

Explanation:

Dinitrogen Trisulfide N2S3 Molecular Weight -- EndMemo.

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3 years ago

Read 2 more answers

A solution contains 3.1 mM Zn(NO3)2 and 4.2 mM Ca(NO3)2. The p-function for Zn2+ is _____, and the p-function for NO3- is _____.

seropon [69]

Answer: The p-function of $Zn^{2+}$ and $NO_3^{-}$ ions are 2.51 and 2.14 respectively.

Explanation:

p-function is defined as the negative logarithm of any concentration.

We are given:

Millimolar concentration of zinc nitrate = 3.1 mM

Millimolar concentration of calcium nitrate = 4.2 mM

Converting this into molar concentration, we use the conversion factor:

1 M = 1000 mM

Concentration of zinc nitrate = 0.0031 M = 0.0031 mol/L

1 mole of zinc nitrate produces 1 mole of zinc ions and 2 moles of nitrate ions

Concentration of zinc ions = 0.0031 M

Concentration of nitrate ions in zinc nitrate, $M_1=(2\times 0.0031)=0.0062M$

Concentration of calcium nitrate = 0.0042 M = 0.0042 mol/L

1 mole of calcium nitrate produces 1 mole of calcium ions and 2 moles of nitrate ions

Concentration of calcium ions = 0.0042 M

Concentration of nitrate ions in calcium nitrate, $M_2=(2\times 0.0042)=0.0084M$

To calculate the concentration of nitrate ions in the solution, we use the equation:

$M=\frac{M_1V_1+M_2V_2}{V_1+V_2}$

Putting values in above equation, we get:

$M=\frac{(0.0062\times 1)+(0.0084\times 1)}{1+1}\\\\M=0.0073M$

Calculating the p-function of zinc ions and nitrate ions in the solution:

For zinc ions:

$\text{p-function of }Zn^{2+}\text{ ions}=-\log[Zn^{2+}]$

$\text{p-function of }Zn^{2+}\text{ ions}=-\log(0.0031)\\\\\text{p-function of }Zn^{2+}\text{ ions}=2.51$

For nitrate ions:

$\text{p-function of }NO_3^{-}\text{ ions}=-\log[NO_3^{-}]$

$\text{p-function of }NO_3^{-}\text{ ions}=-\log(0.0073)\\\\\text{p-function of }NO_3^{-}\text{ ions}=2.14$

Hence, the p-function of $Zn^{2+}$ and $NO_3^{-}$ ions are 2.51 and 2.14 respectively.

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3 years ago

Need help with these three questions!!!

Elis [28]

Answer:

6. In order from left to right the balanced coeficcients are,

6, 1, 2, 3

8. $C_{7}H_{10}_{(l)}+6H_{(g)}=C_{7}H_{16}_{(l)$

9. In order from left to right the balanced coeficcients are,

1, 11, 7, 8

4 0

3 years ago