The magnitude of the electrostatic force on each one will be ¼ of its initial electrosatic force
<h3>Further explanation</h3>
Electric charge consists of two types i.e. positively electric charge and negatively electric charge.
There was a famous scientist who investigated about this charges. His name is Coulomb and succeeded in formulating the force of attraction or repulsion between two charges i.e. :

<em>F = electric force (N)</em>
<em>k = electric constant (N m² / C²)</em>
<em>q = electric charge (C)</em>
<em>r = distance between charges (m)</em>
<em>The value of k in a vacuum = 9 x 10⁹ (N m² / C²)</em>
Let's tackle the problem now !
<u>Given:</u>
Q₁' = ½ Q₁
Q₂' = ½ Q₂
<u>Unknown:</u>
F' = ?
<u>Solution:</u>
For this problem we will use a comparison of the two conditions as follows.





<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Static Electricity
Keywords: Series , Parallel , Measurement , Absolute , Error , Combination , Resistor , Resistance , Ohm , Charge , Small , Forces