two identical small charged spheres are a certain distance apart, and each one initially experiences an electrostatic force of m
agnitude f due to the other. with time, charge gradually diminishes on both spheres by leaking off. when each of the spheres has lost half its initial charge, what will be the magnitude of the electrostatic force on each one?
2 answers:
The magnitude of the electrostatic force on each one will be ¼ of its initial electrosatic force
<h3>Further explanation</h3>Electric charge consists of two types i.e. positively electric charge and negatively electric charge.
There was a famous scientist who investigated about this charges. His name is Coulomb and succeeded in formulating the force of attraction or repulsion between two charges i.e. :
<em>F = electric force (N)</em>
<em>k = electric constant (N m² / C²)</em>
<em>q = electric charge (C)</em>
<em>r = distance between charges (m)</em>
<em>The value of k in a vacuum = 9 x 10⁹ (N m² / C²)</em>
Let's tackle the problem now !
<u>Given:</u>
Q₁' = ½ Q₁
Q₂' = ½ Q₂
<u>Unknown:</u>
F' = ?
<u>Solution:</u>
For this problem we will use a comparison of the two conditions as follows.
- The three resistors : brainly.com/question/9503202
- A series circuit : brainly.com/question/1518810
- Compare and contrast a series and parallel circuit : brainly.com/question/539204
Grade: High School
Subject: Physics
Chapter: Static Electricity
Keywords: Series , Parallel , Measurement , Absolute , Error , Combination , Resistor , Resistance , Ohm , Charge , Small , Forces
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ex 1) The sailboat moves north, while the wind moves from southeast. This means the angle between the direction of the boat and the wind is
.
Calling F the force of the wind, and
the distance covered by the boat, the work done by the wind is:
The total time of the motion is
and therefore the power of the wind is
ex 2) First of all, let's calculate the length of the ramp. Given the two sizes 2.00 m and 6.00 m, we have
The mechanical advantage (MA) of the ramp is the ratio between the output load (W) and the input force (F). The output load is the weight of the load, mg, therefore:
Finally, the efficiency
of the ramp is the ratio between the output energy and the work done. The output energy is simply the potential energy (Ep) of the load, which is mgh, where h is the height of the ramp. The work done W is the product between the input force, F, and the displacement of the load, which is the length of the ramp: Fd. Therefore:
ex 3) the graph is missing
ex 4) We know that the power is the ratio between the work done W and the time t:
But we can rewrite the work as
where F is the force applied, d the displacement of rock and![\theta=60^{\circ]](https://tex.z-dn.net/?f=%5Ctheta%3D60%5E%7B%5Ccirc%5D)
is the angle between the direction of the force and the displacement (3 m).
Therefore we can rewrite the power as
where
is the velocity, Using the data of the exercise, we can then find the force, F:
and now we can also calculate the work, which is
ex 1) The sailboat moves north, while the wind moves from southeast. This means the angle between the direction of the boat and the wind is
Calling F the force of the wind, and
The total time of the motion is
ex 2) First of all, let's calculate the length of the ramp. Given the two sizes 2.00 m and 6.00 m, we have
The mechanical advantage (MA) of the ramp is the ratio between the output load (W) and the input force (F). The output load is the weight of the load, mg, therefore:
Finally, the efficiency
ex 3) the graph is missing
ex 4) We know that the power is the ratio between the work done W and the time t:
But we can rewrite the work as
where F is the force applied, d the displacement of rock and
Therefore we can rewrite the power as
where
and now we can also calculate the work, which is