Answer:
Object will float.
Explanation:
Total force on the body = Weight of body + Buoyancy force on body.
Weight of body = 15 N downwards = 15 N
Buoyancy force on body = 17 N upwards = -17 N
Total force on body = 15 - 17 = -2 N = 2 N upwards
So, the body will float.
Object will float.
Answer:
Explanation:
f =
T = 120 N
L = 3.00 m
(m/L) = 120 g/cm(100 cm/m / 1000 g/kg) = 12 kg/m
(wow that's massive for a "rope")
f = )
f = /6 = 0.527 Hz
This is a completely silly exercise unless this "rope" is in space somewhere as the weight of the rope (353 N on earth) far exceeds the tension applied.
A much more reasonable linear density would be 120 g/m resulting in a frequency of √1000/6 = 5.27 Hz on a rope that weighs only 3.5 N
Answer:
I think it's A, I'm not sure though
Answer:
D) 3.0
Explanation:
As we know that
So,
Now
T = True weight of object
= mg
= 245 N
W = apparent weight = 200 N
= density of object
Now we use the formula
buoyancy force = True weight - W
600 V (9.8) = 45
V = 0.007653
m = 25 kg
And as we know that
= 3266.7
Now
specific gravity is
= 3.2
Hence, the correct option is d.