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likoan [24]
3 years ago
7

Type O blood is known as the universal donor why is this so?

Physics
2 answers:
bagirrra123 [75]3 years ago
7 0
Because their blood cells could be transfused to any blood type
hope I helped you
Plsss help me with brainliest
UkoKoshka [18]3 years ago
4 0
People with O<span> negative </span>blood<span> are </span>universal<span> red </span>blood<span> cell </span>donors<span>. This means that their red </span>blood<span> cells can be transfused to any </span>blood type<span>. </span>O<span> negative is the </span>universal donor<span>.</span>
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WORTH 50 POINTSSSS!!!!!!!! don't lie either if you do I will report your answer and get my points back idc !!!!!!
BARSIC [14]

Answer:

b

Explanation:

3 0
2 years ago
What is an non example of Cultural diffusion
belka [17]
Beliefs is a non example
4 0
3 years ago
A car travels at 60 miles per hour. How much time does it take the car to travel 30 miles? Select one: a. 1 hour b. 1/2 hour c.
andreev551 [17]
The car is traveling at 60 miles per hour. Theoretically, at this pace, It'll take (B.), 1/2 an hour.


Brainliest?


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4 0
3 years ago
Read 2 more answers
Temperature change time base problem. Suppose V = 24 V, I = 0.1 A, for water: mw = 51 gm, cw = 4.18 J/gm ∘K-1, for resistor: mr
nirvana33 [79]

Answer:

t = 444.125 sec

Explanation:

Given data:

V = 24 volt

I  = 0.1 ampere

mass of water mw = 51 gm

cr = 4.18 J/gm degree K^-1

mass of resistor = 8 gm

cr = 3.7 J/gm degree K^-1

we know that power is given as

Power P = VI

But P =E/t

so equating both side we have

\frac{E}{t} = VI

solving for t

t = \frac{E}{VI}

t = \frac{m_w C_w \Delta T}{VI}

t = \frac{51 \times 4.18 \times (5 -0)}{24\times 0.1}

t = 444.125 sec

5 0
3 years ago
Read 2 more answers
A wire of length 5mm and Diameter 2m extends by 0.25 when a force of 50N was use. calculate the
bazaltina [42]

Answer and Explanation:

Data provided in the question

Force = 50N

Length = 5mm

diameter = 2.0m = 2\times 10^{-3}

Extended by = 0.25mm = 0.25\times 10^{-3}

Based on the above information, the calculation is as follows

a. The Stress of the wire is

= \frac{force\ applied}{area\ of \ circle}

here area of circle = perpendicular to the are i.e cross-sectional  i.e

= \frac{\pi d^{2}}{4}

= \frac{\pi(2\times 10^{-3})^2}{4}

Now place these above values to the above formula

= \frac{4\times 50}{\pi\times 4 \times 10^{-6}} \\\\ = \frac{50}{\pi}

= 15.92 MPa

As 1Pa = 1 by N m^2

So,

MPa = 10^6 N m^2

b. Now the strain of the wire is

= \frac{Change\ in\ length}{initial\ length} \\\\ = \frac{0.25\times 10^{-3}}{5}

= 5 \times 10^{-5}

3 0
3 years ago
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