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n200080 [17]
3 years ago
9

An electron travels with speed 6.0×10^6 m/s between the two parallel charged plates shown in the figure. The plates are separate

d by 1.0 cm and are charged by a 200 Volt battery.
What magnetic field strength will allow the electron to pass between the plates without being deflected?
Physics
1 answer:
svlad2 [7]3 years ago
5 0

Answer:

B= 3.33 m T

Explanation:

Given that

Speed ,C= 6 x 10⁶  m/s

d= 1 cm = 0.01 m

V= 200 V

The electric field E given as

V= E .d

E=Electric field

d=Distance

V=Voltage

200 = 0.01 x E

E=20000 V/m

The relationship between magnetic and electric field given as

E= C x B

20000 = 6 x 10⁶   x B

B =3333.333 x 10⁻⁶ T

B= 3.33 x 10⁻³ T

B= 3.33 m T

Therefore the magnetic filed will be 3.33 m T.

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An object with less mass
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How far can a person run in 15 minutes if he or she runs at an average speed of 16 km/hr
Studentka2010 [4]
4 km/hr. There are four quarters in an hour, so just divide 16 by 4 and you get 4. It is directly proportional.
6 0
3 years ago
Projectile A is launched horizontally at a speed of 20. Meters per second from the top of a cliff and strikes a level surface be
miv72 [106K]

consider the motion of projectile A in vertical direction :

v₀ = initial velocity of projectile A in vertical direction = 0 m/s         (since the projectile was launched horizontally)

a = acceleration of the projectile = g = acceleration due to gravity = 9.8 m/s²

t = time of travel for projectile A = 3.0 seconds

Y = vertical displacement of projectile A = height of the cliff = h = ?

using the kinematics equation along the vertical direction as

Y = v₀ t + (0.5) a t²

h = (0) (3.0) + (0.5) (9.8) (3.0)²

h = 44.1 m

4 0
3 years ago
Calculate the object's velocity as shown on the position-time graph,
Cloud [144]

Answer:

10 m/s

Explanation:

The following data were obtained from the question:

Initial Displacement (d1) = 10 m

Final Displacement (d2) = 60 m

Initial time (t1) = 0 s

Final time (t2) = 5 s

Velocity (v) =.?

Next, we shall determine the change in displacement of the object and likewise the change in time.

This can be obtained as follow:

Initial Displacement (d1) = 10 m

Final Displacement (d2) = 60 m

Change in displacement (Δd) = d2 – d1

Change in displacement (Δd) = 60 – 10

Change in displacement (Δd) = 50 m

Initial time (t1) = 0 s

Final time (t2) = 5 s

Change in time (Δt) = t2 – t1

Change in time (Δt) = 5 – 0

Change in time (Δt) = 5 s

Finally, we shall shall calculate the velocity of the object as illustrated below:

Change in displacement (Δd) = 50 m

Change in time (Δt) = 5 s

Velocity (v) =.?

v = Δd/Δt

v = 50/5

v = 10 m/s

Therefore, the velocity of the object is 10 m/s.

4 0
3 years ago
What does it mean for PE to be dependent on the reference level?
Anastasy [175]

Answer:

The potential energy of an object is the energy possessed by the object due to its position in a gravitational field.

Mathematically, it is given by:

PE=mgh

where

m is the mass of the object

g is the acceleration due to gravity at the location of the object

h is the height of the object

As we can see, the potential energy depends on the height of the object, h.

However, this height is relative, since it can be measured using different reference levels.

Generally, the reference level is taken to be the ground; so for example, an object located at the top of a cliff 40 m above the ground, has

h = 40 m

But this value is of course relative, since we can also take the reference level to be the top of the cliff, so in that case, we would have

h = 0

3 0
3 years ago
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