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alexandr1967 [171]
3 years ago
8

Find the length of a pendulum that oscillates with a frequency of 0.16 hz. the acceleration due to gravity is 9.81 m/s 2 . answe

r in units of m.
Physics
1 answer:
Vsevolod [243]3 years ago
7 0
The period of the pendulum is the reciprocal of the frequency:
T= \frac{1}{f}= \frac{1}{0.16 Hz}=6.25 s

The period of the pendulum is given by
T=2 \pi  \frac{L}{g}
where L is the length of the pendulum, and g the acceleration of gravity. By re-arranging the formula and using the value of T we found before, we can  calculate the length of the pendulum L:
L=g  \frac{T^2}{(2 \pi)^2}=(9.81 m/s^2)  \frac{(6.25 s)^2}{(2 \pi)^2}=9.71 m
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