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xeze [42]
3 years ago
11

An engine performs 6400 j of work on a motorbike the motorbike and the rider have a combined mass of 200 kg if the bike started

at rest what is the speed of the bike after the work is performed
Physics
1 answer:
spin [16.1K]3 years ago
4 0

The work done by the engine is converted into kinetic energy of the motorbike+rider system:

W=K=\frac{1}{2}mv^2

where

W=6400 J is the work

m=200 kg is the mass of the system

v is the speed acquired by the motorbike


Rearranging the equation and substituting the numbers in, we find

v=\sqrt{\frac{2W}{m}} =\sqrt{\frac{2(6400 J)}{200 kg}} =8 m/s

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