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Svetllana [295]
3 years ago
10

Which of the following provides evidence to support Bohr's theory of atomic orbitals?

Chemistry
2 answers:
NeX [460]3 years ago
5 0

Answer:

C. Spectrum of colors emitted by gas

Explanation:

Neils Bohr model of atom suggested that orbital electrons are divided into spherical orbits or energy levels around the central nucleus. In essence, electrons are located at various energy levels round the nucleus. His concept explained the discrete lines in the atomic spectrum of hydrogen. He suggested that electrons can move between different energy levels by simply gaining or losing energy.

bezimeni [28]3 years ago
4 0

Answer: C. Spectrum of Colors

A. Gold Foil Experiment

B. Plum pudding model

<u>C. Spectrum of colors emitted by gas</u>

D. Radiation produced when beryllium is bombarded with alpha particles

Explanation:

I just took the test and C. Spectrum Colors is the correct answer!

Good Luck!!

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Which of the following is not a base
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3 years ago
At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. What partial pressur
fenix001 [56]

At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the  partial pressure of He would give a solubility of 0.200 M.

<h3>What is Henry's Law ?</h3>

Henry's Law is a gas law states that at a constant temperature the amount of gas that dissolved in a liquid is directly proportional to the partial pressure of that gas.

<h3>What is relationship between Henry's Law constant and Solubility ?</h3>

The solubility of gas is directly proportional to partial pressure.

It is expressed as:

S_{\text{gas}} = K_{H} P_{\text{gas}}

where,

S_{\text{gas}} = Solubility of gas

K_{H} = Henry's Law constant

P_{\text{gas}} = Partial pressure of gas

Now put the values in above expression we get

S_{\text{gas}} = K_{H} P_{\text{gas}}

0.080M = K_{H} × 1.7 atm

K_{H} = \frac{0.080\ M}{1.7\ \text{atm}}

      = 0.047 M/atm

Now we have to find the partial pressure of He

S_{\text{gas}} = K_{H} P_{\text{gas}}

0.200 M = 0.047 M/atm × P_{\text{gas}}

P_{\text{gas}} = \frac{0.200 M}{0.047\ \text{M/atm}}

       = 4.25 atm

Thus from the above conclusion we can say that At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the  partial pressure of He would give a solubility of 0.200 M.

Learn more about the Henry's Law here: brainly.com/question/23204201

#SPJ4

3 0
1 year ago
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