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-BARSIC- [3]
3 years ago
15

You finally earn your drivers license and are extremely excited to start driving! It is the middle of winter and all 4 tires on

your car look like the air level is low. After checking for air leaks you have found none. The last time you filled the tires was summer. What is the reason for the low pressure?
Chemistry
1 answer:
anygoal [31]3 years ago
5 0

Answer: Tires air condenses and when it condenses it takes up less room.

Explanation: Hope that helps!

You might be interested in
The complete combustion of propane (C3H8) in the presence of oxygen yields CO2 and H2O: C3H8 (g) + 5O2 (g) 3CO2 (g) + 4H2O (g) a
mixas84 [53]

Answer:

26.9 L is the volume of CO₂, we obtained

Explanation:

The reaction is: C₃H₈(g) + 5O₂(g)  →  3CO₂ (g) + 4H₂O (g)

Let's determine the reactants moles:

27.5 g . 1mol / 44 g = 0.625 moles

We need density of O₂ to determine mass and then, the moles.

O₂ density = O₂ mass / O₂ volume

O₂ density . O₂ volume = O₂ mass

1.429 g/L . 45L = O₂ mass → 64.3 g

Moles of O₂ → 64.3 g . 1mol/32g = 2.009 moles

Let's find out the limiting reactant:

1 mol of propane needs 5 moles of oxygen to react

Then, 0.625 moles will react with (0.625 . 5)/1 = 3.125 moles of O₂

Oxygen is the limiting reactant, we need 3.125 moles but we only have 2.009 moles

Ratio is 5:3. 5 moles of O₂ produce 3 moles of CO₂

Therefore, 2.009 moles of O₂ must produce (2.009 .3) /5 = 1.21 moles of CO₂. Let's find out the volume, by Ideal Gases Law (STP are 1 atm and 273K, the standard conditions)

1 atm . V = 1.21 moles . 0.082 . 273K

V = (1.21 moles . 0.082 . 273K) / 1atm = 26.9 L

3 0
3 years ago
Hess’s law
Delvig [45]

From the statement of Hess' law, the enthalpy of the reaction A---> C is +90 kJ

<h3>What is Hess' law?</h3>

Hess' law of constant heat summation states that for a multistep reaction, the standard enthalpy of reaction is always constant and is independent of the pathway or intermediate routes taken.

From Hess' law, the enthalpy change for the reaction A ----> C is calculated as follows:

A---> C = A ---> B + B ---> C

ΔH of A---> C = 30 kJ + 60 kJ

ΔH = 90 kJ

Therefore, the enthalpy of the reaction A---> C is +90 kJ

The above reaction A---> C can be shown in the enthalpy diagram below:

A -------------------> C (ΔH = +90 kJ)

\ /

\ / (ΔH = +60 kJ)

(ΔH = +30 J) \ /

> B

Learn more about enthalpy and Hess law at: brainly.com/question/9328637

8 0
2 years ago
__SIO2+__HF--&gt; __ H2SIF6+ __H2O balanced equation
Dima020 [189]
1,6,1,2 that should be the answer
6 0
2 years ago
Summarize: Complete the following statements:
egoroff_w [7]

Answer:

Explanation:

Taking into account the definition of Avogadro's Number, the correct answers are:

1 mole of any element contains 6.023×10²³ atoms

1 mole of any compound contains 6.023×10²³ molecules

You have to know that Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole.

Avogadro's number represents a quantity without an associated physical dimension, so it is considered a pure number that allows describing a physical characteristic without an explicit dimension or unit of expression.

Avogadro's number applies to any substance, because the number of elementary units in a mole of a substance is, by definition, a  constant that does not depend on the material or the type of particle considered.

So, in this case, the correct answers are:

1 mole of any element contains 6.023×10²³ atoms

1 mole of any compound contains 6.023×10²³ molecules

hope that help you mark me as brinilylist pls

4 0
2 years ago
from the following chemical reaction , calculate the moles of mg if 3.5 mol of hcl in reactant mg + 2hcl --&gt; mgcl2 + h2
sveticcg [70]
1.75 moles or 1.8 moles if you’re rounding in terms of sig figs
6 0
2 years ago
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