This is a typical radioactive decay problem which uses the general form:

A = A0e^(-kt)

So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:

A = 192e^(-0.015*55)
<em>A = 84 mg</em>

6 0

3 years ago

Please help me solve this!!

Mice21 [21]

Answer:

Abelito had the greater average speed

Step-by-step explanation:

Given

Bobby:

$Distance =4\ miles$

$Time = 30\ minutes$

Abelito

$Distance = 10\ miles$

$Time = 48\ minutes$

Required:

Who had a greater average speed

Average speed (S) is calculated as:

$S = \frac{Distance}{Time}$

We will make use of mph (miles per hour) as the unit of speed.

For Bobby:

$S_B = \frac{4\ miles}{30\ minutes}$

Convert minute to hour

$S_B = \frac{4\ miles}{0.5\ hr}$

$S_B = 8mph$

For Abelito

$S_A = \frac{10\ miles}{48\ minutes}$

Convert minute to hour

$S_A = \frac{10\ miles}{0.8\ hr}$

$S_A = 12.5mph$

By comparison: 12.5mph > 8mph

Hence: Abelito had the greater average speed

5 0

2 years ago

The quotient of a number and -9 increased by 10.3 is 11.3. What is the equation?

Zepler [3.9K]

Answer:

x/-9+10.3=11.3

Step-by-step explanation:

5 0

2 years ago

Please help me with this question

babymother [125]

Answer:

the perimeter is 48 and the apothem is 72

Step-by-step explanation:

its all just a bunch of multiplication. You multiply 6 (because there is six sides to your perimeter) by 8 and then you have 48. for the apothem. the apothem is a sliver of you perimeter

4 0

2 years ago

point p' is the image of p(5,-5) under a translation by 2 units to the left and 5 units up what are the coordinates of p'​

point p' is the image of p(5,-5) under a translation by 2 units to the left and 5 units up what are the coordinates of p'