Answer:
Therefore,
a) ![\dfrac{N_{1}}{N_{2}}=\dfrac{10}{1}](https://tex.z-dn.net/?f=%5Cdfrac%7BN_%7B1%7D%7D%7BN_%7B2%7D%7D%3D%5Cdfrac%7B10%7D%7B1%7D)
b) I₂ = 2.55 Ampere
c) Power = 30.6 Watts
d) R₁ = 470.58 ohms.
Explanation:
Given:
Let the primary voltage be,
![V_{1}=120\ V](https://tex.z-dn.net/?f=V_%7B1%7D%3D120%5C%20V)
Secondary Voltage,
![V_{2}=12\ V](https://tex.z-dn.net/?f=V_%7B2%7D%3D12%5C%20V)
Secondary Resistance,
![R_{2}=4.7\ ohms](https://tex.z-dn.net/?f=R_%7B2%7D%3D4.7%5C%20ohms)
To Find:
a) ![\dfrac{N_{1}}{N_{2}}=?](https://tex.z-dn.net/?f=%5Cdfrac%7BN_%7B1%7D%7D%7BN_%7B2%7D%7D%3D%3F)
b) I₂ = ?
c) Power = ?
d) R₁ = ?
Solution:
The ratio of primary to secondary turns of the transformer, is the ratio of primary to secondary Voltage and is given by,
![\dfrac{N_{1}}{N_{2}}=\dfrac{V_{1}}{V_{2}}](https://tex.z-dn.net/?f=%5Cdfrac%7BN_%7B1%7D%7D%7BN_%7B2%7D%7D%3D%5Cdfrac%7BV_%7B1%7D%7D%7BV_%7B2%7D%7D)
Substituting the values we get
![\dfrac{N_{1}}{N_{2}}=\dfrac{120}{12}=\dfrac{10}{1}](https://tex.z-dn.net/?f=%5Cdfrac%7BN_%7B1%7D%7D%7BN_%7B2%7D%7D%3D%5Cdfrac%7B120%7D%7B12%7D%3D%5Cdfrac%7B10%7D%7B1%7D)
For, rms current for the secondary supply,
![I_{2}=\dfrac{V_{2}}{R_{2}}](https://tex.z-dn.net/?f=I_%7B2%7D%3D%5Cdfrac%7BV_%7B2%7D%7D%7BR_%7B2%7D%7D)
Substituting the values we get
![I_{2}=\dfrac{12}{4.7}=2.55\ Ampere](https://tex.z-dn.net/?f=I_%7B2%7D%3D%5Cdfrac%7B12%7D%7B4.7%7D%3D2.55%5C%20Ampere)
Now for average power at load,
![Power=V_{2}\times I_{2}](https://tex.z-dn.net/?f=Power%3DV_%7B2%7D%5Ctimes%20I_%7B2%7D)
Substituting the values we get
![Power=12\times 2.55=30.6\ Watts](https://tex.z-dn.net/?f=Power%3D12%5Ctimes%202.55%3D30.6%5C%20Watts)
Now for resistance connected directly across the source line Power will remain same,
![Power=\dfrac{(V_{1})^{2}}{R_{1}}](https://tex.z-dn.net/?f=Power%3D%5Cdfrac%7B%28V_%7B1%7D%29%5E%7B2%7D%7D%7BR_%7B1%7D%7D)
Substituting the values we get
![R_{1}=\dfrac{(V_{1})^{2}}{Power}=\dfrac{14400}{30.6}=470.58\ ohms](https://tex.z-dn.net/?f=R_%7B1%7D%3D%5Cdfrac%7B%28V_%7B1%7D%29%5E%7B2%7D%7D%7BPower%7D%3D%5Cdfrac%7B14400%7D%7B30.6%7D%3D470.58%5C%20ohms)
Therefore,
a) ![\dfrac{N_{1}}{N_{2}}=\dfrac{10}{1}](https://tex.z-dn.net/?f=%5Cdfrac%7BN_%7B1%7D%7D%7BN_%7B2%7D%7D%3D%5Cdfrac%7B10%7D%7B1%7D)
b) I₂ = 2.55 Ampere
c) Power = 30.6 Watts
d) R₁ = 470.58 ohms.
Answer:
a) time t1 = 2.14s
b) initial angular speed w1 = 6 rad/s
Explanation:
Given that;
Initial Angular velocity = w1
Angular distance = s = 65 rad
time = t = 5 s
Angular acceleration a = 2.80 rad/s^2
Using the equation of motion;
s = w1t + (at^2)/2
w1 = (s-0.5(at^2))/t
Substituting the values;
w1 = (65 - (0.5×2.8×5^2))/5
w1 = 6rad/s
Time to reach w1 from rest;
w1 = at1
t1 = w1/a = 6/2.8 = 2.14s
a) time t1 = 2.14s
b) initial angular speed w1 = 6 rad/s
Answer: liquid
explanation: 1 liter is a measurement of liquids, not solids, or gases.
Liquids also have a set volume, but can flow to take the shape of the bottom of their container.
Answer:
![72.12\ \text{A/m}^2](https://tex.z-dn.net/?f=72.12%5C%20%5Ctext%7BA%2Fm%7D%5E2)
south
cross sectional area of the beam
Explanation:
v = Velocity of ions = ![4.6\times 10^5\ \text{m/s}](https://tex.z-dn.net/?f=4.6%5Ctimes%2010%5E5%5C%20%5Ctext%7Bm%2Fs%7D)
Number of ions per
= ![4.9\times 10^8](https://tex.z-dn.net/?f=4.9%5Ctimes%2010%5E8)
Charge density would be the product of number of ions per
and the charge of electrons multiplied by 2 as they are doubly charged.
![\rho_q=4.9\times 10^8\times 10^6\times 2\times 1.6\times 10^{-19}\\\Rightarrow \rho_q=0.0001568\ \text{C/m}^3](https://tex.z-dn.net/?f=%5Crho_q%3D4.9%5Ctimes%2010%5E8%5Ctimes%2010%5E6%5Ctimes%202%5Ctimes%201.6%5Ctimes%2010%5E%7B-19%7D%5C%5C%5CRightarrow%20%5Crho_q%3D0.0001568%5C%20%5Ctext%7BC%2Fm%7D%5E3)
Current density is given by
![J=\rho_qv\\\Rightarrow J=0.0001568\times 4.6\times 10^5\\\Rightarrow J=72.12\ \text{A/m}^2](https://tex.z-dn.net/?f=J%3D%5Crho_qv%5C%5C%5CRightarrow%20J%3D0.0001568%5Ctimes%204.6%5Ctimes%2010%5E5%5C%5C%5CRightarrow%20J%3D72.12%5C%20%5Ctext%7BA%2Fm%7D%5E2)
The current density is ![72.12\ \text{A/m}^2](https://tex.z-dn.net/?f=72.12%5C%20%5Ctext%7BA%2Fm%7D%5E2)
The direction of the current density is opposite to the movement of the charged particle. The particles are moving north so the direction of current density will be to the south.
Current is given by
![I=JA](https://tex.z-dn.net/?f=I%3DJA)
where A is the cross sectional area of the beam .
So the cross sectional area of the beam is required to determine the total current in this ion beam.
Answer:
When a net force acts on a body it produces acceleration in body the magnitude of tries acceleration is directly proportional to the net force acting and inversely proportional to the mass of the body
Mathematical form
F=ma
Explanation:
I hope it will help you