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Rus_ich [418]
3 years ago
8

Does a material have less mass when it has contracted?

Physics
1 answer:
Lyrx [107]3 years ago
8 0

Answer:No

Explanation:The amount of mass is the amount of matter in an object if it is contracted the mass stays the same, it is just more dense

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True or false a reference point is the object to which we compare another object's motion
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True, because for example you are on a bus and you want to know if you are moving or not so you look at a house which doesn't move and stays stationary.
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4 years ago
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1) A car is moving to the right with the constant speed of 1.2 m/s. If the car starts
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(100, 108)
Due to
1.2x90=108

100, 108
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3 years ago
an object has a constant acceleration of 3.2 m/s^2.at a certain instant its velocity is 10 m/s . what is its velocity after 5 se
aleksandrvk [35]

So here, you're looking for distance. The formula is D=vt+1/2at^2.

Lets plug in the informations.

10 m/s is our v (initial velocity)

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10m/s(5)+1/2(3.2m/s+5^2)

50m/s+1/2(28.2)

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5 0
3 years ago
Every surface has different ____________________ of friction.
dedylja [7]

Answer:

amounts

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3 0
3 years ago
A small object with momentum 7.0 kg∙m/s approaches head-on a large object at rest. The small object bounces straight back with a
EastWind [94]

Answer:

The magnitude of the large object's momentum change is 3 kilogram-meters per second.

Explanation:

Under the assumption that no external forces are exerted on both the small object and the big object, whose situation is described by the Principle of Momentum Conservation:

p_{S,1}+p_{B,1} = p_{S,2}+p_{B,2} (1)

Where:

p_{S,1}, p_{S,2} - Initial and final momemtums of the small object, measured in kilogram-meters per second.

p_{B,1}, p_{B,2} - Initial and final momentums of the big object, measured in kilogram-meters per second.

If we know that p_{S,1} = 7\,\frac{kg\cdot m}{s}, p_{B,1} = 0\,\frac{kg\cdot m}{s} and p_{S, 2} = 4\,\frac{kg\cdot m}{s}, then the final momentum of the big object is:

7\,\frac{kg\cdot m}{s} + 0\,\frac{kg\cdot m}{s} = 4\,\frac{kg\cdot m}{s}+p_{B,2}

p_{B,2} = 3\,\frac{kg\cdot m}{s}

The magnitude of the large object's momentum change is:

p_{B,2}-p_{B,1} = 3\,\frac{kg\cdot m}{s}-0\,\frac{kg\cdot m}{s}

p_{B,2}-p_{B,1} = 3\,\frac{kg\cdot m}{s}

The magnitude of the large object's momentum change is 3 kilogram-meters per second.

4 0
3 years ago
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