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Rus_ich [418]
3 years ago
8

Does a material have less mass when it has contracted?

Physics
1 answer:
Lyrx [107]3 years ago
8 0

Answer:No

Explanation:The amount of mass is the amount of matter in an object if it is contracted the mass stays the same, it is just more dense

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Is walking just a constant state of falling?
atroni [7]

Answer:

Yes. Walking is controlled falling because you need to let go in order to move forward. If you never let your foot fall, your movements would be stilted and robotic. And according to medical engineers," When we walk normally we are constantly correcting tiny falls to keep ourselves stable."

Explanation:

8 0
3 years ago
A car moves with an initial velocity of 19 m/s due north. (Part A) Find the velocity of the car after 5.6 s if its acceleration
galben [10]

Answer

Assuming

east is the positive x direction

north is the positive y direction

initial velocity , u = 19 j m/s

a) acceleration , a = 1.6 j m/s^2

Using first equation of motion

v = u + a × t

v = 19 + 5.6× 1.6

v = 28 j m/s

the velocity of the car after 5.6 s is 28 m/s north

b)

acceleration , a = -1.5 j m/s^2

Using first equation of motion

v = u + a × t

v = 19 - 5.6 ×1.5

v = 10.6 j m/s

the velocity of the car after 5.6 s is 10.6 m/s north

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3 years ago
A ball rolls across a floor with an acceleration of 0.100 m/s2 in a direction opposite to its velocity. The ball has a velocity
Westkost [7]

Answer:

4.15 m/s

Explanation:

Its given that acceleration is 0.1 m/s² with a direction opposite to the velocity. Since, the direction of acceleration is opposite to the velocity, this gives us a hint that the velocity is decreasing and so acceleration would be negative.

i.e.

acceleration = a = - 0.1 m/s²

Distance covered = S = 6m

Velocity after covering 6 meters = Final velocity = v_{f} = 4 m/s

We need to find the initial speed, which will be the same as the magnitude of initial velocity.

Initial velocity = v_{i} =  ?

3rd equation of motion relates the acceleration, distance, final velocity and initial velocity as:

2aS = (v_{f})^{2}-(v_{i})^{2}

Using the known values in the formula, we get:

2(-0.1)(6)=(4)^{2}- (v_{i})^{2}\\\\ (v_{i})^{2}=16+1.2\\\\ (v_{i})^{2}=17.2\\\\ v_{i}=4.15

Thus, the initial speed of the ball was 4.15 m/s

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