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Kitty [74]
3 years ago
7

Which of the following instruments is not typically an electronic instrument, but could be enhanced with the help of microphones

? acoustic guitar synthesizer theremin electronic organ
Physics
2 answers:
tino4ka555 [31]3 years ago
7 0

it is the acoustic guitar

TiliK225 [7]3 years ago
6 0
The synthesizer, the Theremin, and the electronic organ are totally electronic
instruments.  They don't make any sound at all without electronic circuits and
electric power.

The acoustic guitar is not inherently an electronic instrument.  It can be made
louder with microphones, and given special effects with other electronic stuff.
Whether any of this is actually an 'enhancement' is open to debate.

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The hour, minute, and second hands on a clock are 0.25 m , 0.31 m , and 0.34 m long, respectively.
sp2606 [1]

In 1 hour, the hour hand sweeps across 1/12 of the clock's face. In 40 min, the hour hand travels (40 min)/(60 min) = 2/3 of the path it covers in an hour, so a total of 1/12 × 2/3 = 1/18 of the clock's face. This hand traces out a circle with radius 0.25 m, so in 40 min its tip traces out 1/18 of this circle's radius, or

1/18 × 2<em>π</em> (0.25 m) ≈ 0.087 m

The minute hand traverses (40 min)/(60 min) = 2/3 of the clock's face, so it traces out 2/3 of the circumference of a circle with radius 0.31 m:

2/3 × 2<em>π</em> (0.31 m) ≈ 1.3 m

The second hand completes 1 revolution each minute, so in 40 min it would fully trace the circumference of a circle with radius 0.34 m a total of 40 times, so it covers a distance of

40 × 2<em>π</em> (0.34 m) ≈ 85 m

6 0
3 years ago
A p-wave arrives at 3:00:00 and the s-wave arrives at 3:07:20, what is the exact distance that the seismic station is away from
maxonik [38]

The exact distance from the seismic station to the epicenter is 6000 km.

<h3>Epicenter of earthquake</h3>

The earthquake's epicenter is the point above the fault location on the earth's surface.

Given that:

A p-wave arrives at 3:00:00 and the s-wave arrives at 3:07:20.

Difference in arrival time = 3:07:20 - 3:00:00 = 7 minutes 20 seconds

From the earthquake time travel graph, a time difference of 7 min 20 sec is at x = 6

The exact distance from the seismic station to the epicenter is 6000 km.

Find out more on Epicenter of earthquake at: brainly.com/question/1969968

4 0
2 years ago
A"boat"is"moving"to"the"right"at"5"m/s"with"respect"to"the"water."A"wave"moving"to"the"left,"opposite"the"motion"of"the"boat."Th
s2008m [1.1K]

Answer:

0.99m

Explanation:

Firs you calculate the relative velocity between the boat and the wave. The velocity of the boat is 5m/s and the velocity of the wave is given by:

v=\lambda f=\lambda\frac{1}{T}=(110m)\frac{1}{8.3s}=13.25\frac{m}{s}

the relative velocity is:

v'=13.25m/s-5m/s=8.25\frac{m}{s}

This velocity is used to know which is the distance traveled by the boat after 20 seconds:

x'=v't=(8.25m/s)(20s)=165m

Next, you use the general for of a wave:

f(x,t)=Acos(kx-\omega t)=Acos(\frac{2\pi}{\lambda}x-\omega t)

you take the amplitude as 2.0/2 = 1.0m.

\omega=\frac{2\pi}{T}=\frac{2\pi}{8.3s}=0.75\frac{rad}{s}

by replacing the values of the parameters in f(x,t) you obtain the vertical displacement of the boat:

f(165,20)=1.0m\ cos(\frac{2\pi}{110m}(165)-(0.75\frac{rad}{s})(20s))\\\\f(165,20)=0.99m

6 0
4 years ago
Seismic waves do not travel along the Earth’s surface. Please select the best answer from the choices provided
mario62 [17]
<span>The correct answer to the question that is stated above is obviously letter b, false. 

</span>Seismic waves travel along the Earth’s surface.They are <span>waves of </span>energy<span> that travel through the </span>Earth<span>'s layers.  These waves are a result of an </span>earthquake <span>, </span>volcanic<span> eruptions, magma movement and large </span>landslides.
3 0
3 years ago
Read 2 more answers
An object is 2.0 cm from a double convex lens with a focal length of 1.5 cm. Calculate the image distance
Tomtit [17]

Answer:

0.857 cm

Explanation:

We are given that:

The focal length for a convex lens to be (f) = 1.5cm

The object distance (u) = - 2.0 cm

We are to determine the image distance (v) = ??? cm

By applying the lens formula:

\dfrac{1}{f} = \dfrac{1}{u}+\dfrac{1}{v}

By rearrangement and making (v) the subject of the above formula:

v = \dfrac{uf}{u-f}

replacing the given values:

v = \dfrac{(-2.0)(1.5)}{(-2.0 -1.5)}

v = \dfrac{-3.0}{(-3.5)}

v = 0.857 cm

3 0
3 years ago
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