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Rus_ich [418]
3 years ago
6

The fact that your eyes rotate in their sockets, either getting closer or farther from each other, as an object changes its dist

ance from you is a binocular distance cue called ________.
Physics
1 answer:
marta [7]3 years ago
5 0

Answer:

convergence

Explanation:

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1. The Moon's mass is 7.34 x 1022 kg, and it is 3.8 x 105 km away from Earth. Earth's
sineoko [7]

Answer:

2.03 x 10²⁴N

Explanation:

Given parameters:

Mass of moon = 7.34 x 10²²kg

Mass of the earth  = 5.97 x 10²⁴kg

Distance  = 3.8 x 10⁵km

Unknown:

Gravitational force of attraction  = ?

Solution:

To find the gravitational force of attraction between the masses, we use the expression below;

   F = \frac{Gm_{1} m_{2}  }{r^{2} }

G is the universal gravitation constant

m is the mass

1 and 2 represents moon and earth

r is  the distance

  F = \frac{6.67 x 10^{-11}  x 7.34 x 10^{22} x 5.97 x 10^{24}  }{(3.8 x 10^{5})^{2}  }

 F = \frac{2.92 x 10^{35} }{1.44 x 10^{11} }  = 2.03 x 10²⁴N

8 0
3 years ago
True or False: As distance between 2 objects increases, the gravitational force decreases
VikaD [51]

Answer:

True

Explanation:

Because it is:)

5 0
3 years ago
This exercise uses the radioactive decay model. After 3 days a sample of radon-222 has decayed to 58% of its original amount. (a
Vadim26 [7]

Answer: a) 3.85 days

b) 10.54 days

Explanation:-

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = ?

t = time taken for decomposition  = 3 days

a = let initial amount of the reactant  = 100 g

a - x = amount left after decay process  = \frac{58}{100}\times 100=58g

First we have to calculate the rate constant, we use the formula :

Now put all the given values in above equation, we get

k=\frac{2.303}{3}\log\frac{100}{58}

k=0.18days^{-1}

a) Half-life of radon-222:

t_{\frac{1}{2}}=\frac{0.693}{k}

t_{\frac{1}{2}}=\frac{0.693}{0.18}=3.85days

Thus half-life of radon-222 is 3.85 days.

b) Time taken for the sample to decay to 15% of its original amount:

where,

k = rate constant  = 0.18days^{-1}

t = time taken for decomposition  = ?

a = let initial amount of the reactant  = 100 g

a - x = amount left after decay process  = \frac{15}{100}\times 100=15g

t=\frac{2.303}{0.18}\log\frac{100}{15}

t=10.54days

Thus it will take 10.54 days for the sample to decay to 15% of its original amount.

3 0
3 years ago
While playing Quidditch you throw the quaffle straight down to the person below you at
oee [108]

Answer:

the ans will be because it has 1.672

3 0
4 years ago
What did Wundt's pendulum experiment demonstrate?
weeeeeb [17]
C. <span>People need time to shift between two different stimuli.</span>
6 0
3 years ago
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