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sweet-ann [11.9K]
3 years ago
9

A cart rolling down an incline that is 60 meters long. If the cart has a beginning speed of 2.0 m/s and it

Physics
1 answer:
fiasKO [112]3 years ago
3 0

Answer:

4 m/s²

Explanation:

Given:

Δx = 60 m

v₀ = 2.0 m/s

v = 22 m/s

Find: a

v² = v₀² + 2aΔx

(22 m/s)² = (2.0 m/s)² + 2a (60 m)

a = 4 m/s²

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Calculate the acceleration of a 2000-kg.
Paraphin [41]

Answer:

0.25m/s^{2}

Explanation:

In this problem we use Newton's Second Law formula:

A= \frac{F}{M}

F is for the force being applied, in this situation. The 500N is being thrust ed by the engine.

Substitute the force and mass:

A = \frac{500 N}{2000} ms^{2}

A = \frac{1}{4} ms^{2}

A = 0.25m/s^2

6 0
4 years ago
A girl is sitting in a sled sliding horizontally along some snow (there is friction present).
Over [174]

Answer:

159 N

Explanation:

The force of friction, Fr is a product of coefficient of feiction and the normal force. Therefore, Fr=uN where N is the normal force and u is coefficient of friction. Here, we have two coefficients of friction but since it is sliding, then we use coefficient of kinetic energy. Substituting 0.25 for u and 636 N for N then

Fr=0.25*636=159 N

Therefore, the force of friction is equivalent to 159 N

4 0
3 years ago
Salem and Vernonville are 160 miles apart. A car leaves Salem traveling towards​ Vernonville, and another car leaves Vernonville
Paul [167]

Answer:

The speed of car leaves  Vernonville = 45 miles per hour

The speed of car leaves  Salem = 55 miles per hour

Explanation:

Given that distance between Salem and Vernonville = 160 miles

Lest take speed of car which leaves from Vernonville = V miles per hour

So the speed of car which leaves from Salem = V +10 miles per hour

These two car meet at time = 1 hr 36 min = 1.6 hr

Distance travel by car leaves from Salem = x

   x= (V+10) x 1.6    --------1

Distance travel by car leaves from Vernonville = 160 - x

  160 -  x= V x 1.6      ----------2

From equation 1 and 2

160 - (V+10) x 1.6  = V x 1.6

V= 45 miles per hour

So

The speed of car leaves  Vernonville = 45 miles per hour

The speed of car leaves  Salem = 55 miles per hour

8 0
3 years ago
In physics how much energy is required to raise the temp of 9.78kg of water from 40.82c to 52.07c? The specific heat of water in
Sati [7]

Answer:

469.6KJ

Explanation:

Heat energy required can be calculated using the formula

H = mc∆t where

m is the mass of the water

c is the specific heat capacity of the water

∆t is the change in temperature of the water

Given m = 9.78kg

c = 4186j/kg-c.

∆t = 52.07°C - 40.82°C

∆t = 11.25°C

H = 9.78 × 4186 × 11.25

H = 460,564.65Joules

= 460.6KJ

7 0
3 years ago
Read 2 more answers
A very long, straight horizontal wire carries a current such that 8.15×1018 electrons per second pass any given point going from
Maksim231197 [3]

Magnetic field 'B' at a distance 'r' from an substantially large conductor carrying current 'i' = (2x10^ -7)('i' ) / r 

Magnetic field 'B' beyond the wire= (2x10^ -7)(8.15x10^18x1.6x10^ - 19 ) /0.046 =5.7 x10^ -12 tesla 

As electrons move from west to east, the conventional current is from east to west. 

By means of Maxwell's right handed corkscrew rule, the way of magnetic field is from south to north.

3 0
3 years ago
Read 2 more answers
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