Answer:
pressure in the second point is P₂ = 165833.75 Pa
Explanation:
given,
water speed = 1.8 m/s
gauge pressure(P₁) = 51500 Pa
gauge pressure at another point (P₂) = ?
distance of the point at 11.5 m
density of the water = 1000 kg/m³
diameter of the second pipe is double than first.
A₁ V₁ = A₂ V₂
π r² × 1.8 = π × (2r)² × V₂
V₂ = 0.45 m/s
now, gauge pressure at P₂
P₂ = 165833.75 Pa
pressure in the second point is P₂ = 165833.75 Pa
The SI unit of energy is the Joule .
Any kind of energy ... electrical, mechanical, nuclear, solar,
wind etc. It's easy to change from one form to another ... we
do it every day ... and they all have the same unit.
The average force is -212.4 N
Explanation:
We can solve this problem by using the impulse theorem, which states that the impulse exerted on the object (the product of the force exerted and the time) is equal to the change in momentum of the object:
where
F is the net force on the object
is the time
m is the mass
is the change in velocity
In this problem, we have:
m = 26.3 kg
Solving for F, we find
where the negative sign indicates that the direction of the force is opposite to the motion of the object.
Learn more about force and momentum:
brainly.com/question/9484203
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