Moles of ammonium sulfide = 5.80 mol
The formula of ammonium sulfide is (NH₄)₂S
So each molecule of ammonium sulfide has (4 x 2) or 8 atoms of H
One mole of ammonium sulfide has 8 moles of H
5.80 mol of ammonium sulfide has (8 x 5.8) or 46.4 moles of H
As per the definition of Avogadro's number, 1 mole = 6.022 x 10²³ atoms
46.4 moles of H x (6.022 x 10²³ atoms/ 1 mole of H)
= 2.8 x 10²⁵ H atoms
Therefore, 2.8 x 10²⁵ H atoms are in 5.80 mol of ammonium sulfide.
Answer:
=1.4953 moles
Explanation:
Iron (III) Oxide is reduced by carbon (II) oxide into Iron. According to the following equation, One mole of Fe₂O₃ react with 3 moles of CO to produce 2 moles of Fe. Thus the reaction ratio of CO to Fe₂O₃ is 3:1
Fe₂O₃₍s₎ + 3CO → 2Fe₍s₎ + 3CO₂₍g₎
125.6 grams of CO is equivalent to: 125.6g/28.0g/mol
=4.486 moles.
The number of moles of Fe produced by the reaction is:
=(4.486 moles×1)/3
=1.4953 moles
Answer:
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