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ozzi
1 year ago
11

In general terms, how does each of the following atomic properties influence the metallic character of the main-group elements i

n a period?
(d) Effective nuclear charge
Chemistry
1 answer:
vekshin11 year ago
6 0

Metallic property also rises with increasing atomic radius. Metallic character reduces with an increase in the amount of outer electrons.

<h3>What is atomic radius?</h3>

A chemical element's atomic radius, which is typically the average or typical distance between the nucleus's core and the outermost isolated electron, serves as a gauge for the size of an atom. There are numerous non-equivalent definitions of atomic radius since the border is not a clearly defined physical entity. Van der Waals radius, ionic radius, metallic radius, and covalent radius are the four most frequently used definitions of atomic radius. The atomic radius is often measured in a chemically linked condition because it is difficult to isolate individual atoms to measure their radii separately. However, theoretical computations are easier when considering isolated atoms.

To learn more about atomic radius from the given link:

brainly.com/question/13607061

#SPJ4

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45 Gg = [? ]x10!?g<br> ]<br> =<br> ]
nlexa [21]

1. The coefficient (green) is 45

2. The exponent (yellow) is 9

<h3>Conversion scale</h3>

To convert from giga grams (Gg) to grams (g), the following coversion scale can be use:

1 Gg = 10⁹ g

With the above convesion scale, we can convert 45 Gg to g as follow

1 Gg = 10⁹ g

Therefore,

45 Gg = 45×10⁹ g

Thus, 45 Gg is equivalent to 45×10⁹ g. Hence, we can conclude as follow:

  • The coefficient (green) is 45
  • The exponent (yellow) is 9

Learn more about conversion:

brainly.com/question/21919505

6 0
2 years ago
I need to know 5 and 6
irina [24]
6-cumbustion reaction
7 0
2 years ago
Select the most likely product for this reaction:
Advocard [28]

Answer:

The answer is B- LiNO3(aq)+H2O(I)

Explanation:

I just did the assignment also UNUS ANNUS

3 0
3 years ago
Read 2 more answers
Use the periodic table to determine the electron configuration for Ca and Pm in noble-gas notation Ca: [Ar]4s2 [Ar]4s1 [Ar]3s2 [
sveta [45]
Answer:

1) Ca: [Ar]4s²
2) Pm: [Xe]6s²4f⁵

Explanation:

1) Ca:

Its atomic number is 20. So it has 20 protons and 20 electrons.

Since it is in the row (period) 4 the noble gas before it is Ar, and the electron configuration is that of Argon whose atomic number is 18.

So, you have two more electrons (20 - 18 = 2) to distribute.

Those two electrons go the the orbital 4s.

Finally, the electron configuration is [Ar] 4s².

2) Pm

The atomic number of Pm is 61, so it has 61 protons and 61 electrons.

Pm is in the row (period) 6. So, the noble gas before Pm is Xe.

The atomic number of Xe is 54.

Therefore, you have to distribute 61 - 54 = 7 electrons on the orbitals 6s and 4f.

The resultant distribution for Pm is: [Xe]6s² 4f⁵.
5 0
2 years ago
Read 2 more answers
What is the frequency of a wave with a wavelength of 6.40x10^4 meters?
yKpoI14uk [10]

Answer:

frequency = 0.47×10⁴ Hz

Explanation:

Given data:

Wavelength of wave = 6.4× 10⁴ m

Frequency of wave = ?

Solution:

Formula:

Speed of wave = wavelength × frequency

Speed of wave = 3 × 10⁸ m/s

Now we will put the values in formula.

3 × 10⁸ m/s = 6.4× 10⁴ m × frequency

frequency = 3 × 10⁸ m/s / 6.4× 10⁴ m

frequency = 0.47×10⁴ /s

s⁻¹ = Hz

frequency = 0.47×10⁴ Hz

Thus the wave with wavelength of 6.4× 10⁴ m have 0.47×10⁴ Hz frequency.

4 0
3 years ago
Read 2 more answers
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