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eimsori [14]
3 years ago
5

Trish has two containers of water for a camping trip. One container holds 2 times as much as the other. The total amount of wate

r is 21 gallons. How much water is in each container?
Mathematics
1 answer:
Bogdan [553]3 years ago
8 0

Answer: 7 gallons; 14 gallons

Step-by-step explanation:

Let the amount of water in the first container be x.

Since one container holds 2 times as much as the other, the second container will be: = x × 2 = 2x

The total amount of water is 21 gallons. This means:

x + 2x = 21

3x = 21

x = 7 gallons

First container = 7 gallons

Second container= 2x = 2×7 = 14 gallons

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motikmotik
There are 3 methods to solve this. elimination substitution and graphing but i am going to use the elimination method.
  x+2y=17
 <u> x-y   =2
</u> 0+3y  =15   ( subtracted down to eliminate the x)( x-x=0, 2y-(-y)=3y, and 17-2=15)
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<u>substitute the y=5 in any of the above equations and solve for x
ie... ( </u>meaning where you find y in the equation, u replace it with a 5)

it will be easier to solve for x in (x-y=2) so i will use that one.
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3 years ago
I really need to know how long it takes the large pipe on its own
Andreyy89

s = hours it takes the small pipe on its own.


L = hours it takes the large pipe on its own.


we know the small pipe can do it in 11 hours total, so s = 11, so, how much of the whole job has the small done in 1 hour only?


well, if it takes 11 hours to do the whole thing, in 1 hour it has done only 1/11 of the whole job.


we know both pipes working together can do it in 6 hours flat. So in 1 hour only, both of them have done only 1/6 of the whole thing.


in that 1 hour, how much has the large one done? well, it has only done 1/L of the job.


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7 0
3 years ago
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scZoUnD [109]

Answer: The required ratio will be

84:1034

Step-by-step explanation:

Since we have given that

Ratio of AD to AB is 3:2

Length of AB = 30 inches

So, it becomes

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So, Length of AD becomes

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Now, at either end , there is a semicircle.

Radius of semicircle along AB is given by

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Area of semicircle along AD and BC is given by

2\times \frac{1}{2}\pi r^2\\\\=\frac{22}{7}\times \frac{45}{2}\times \frac{45}{2}\\\\=\frac{445500}{28}\ in^2

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\frac{4950}{7}+\frac{445500}{28}\\\\=\frac{465300}{28}\ in^2

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1350:\frac{465300}{28}\\\\=1350\times 28:465300\\\\=37800:465300\\\\=84:1034

Hence, the required ratio will be

84:1034

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Answer:

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The dependent Variable depends on the independent variable so, as the number of months change, the total cost changes.
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