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Svetllana [295]
3 years ago
7

The sound intensity 50m from a wailing tornado siren is 0.1W/m2 . What is the sound intensity level 300m from the siren?

Physics
1 answer:
Korvikt [17]3 years ago
3 0

Answer:

I_{300} =2777.7uW/m^{2}

Explanation:

Looking at the formula of intensity we can see that it is inversely proportional to the square of distance and the other terms are all constant

So

I=\frac{P}{A}\\I=\frac{P}{\pi d^{2} }\\I=C\frac{1}{d^{2} }

We can now write the following equality

\frac{I_{300} }{I_{50}}=\frac{50^{2} }{300^{2} }\\  I_{300} =\frac{50^{2} }{300^{2} }*I_{50}\\I_{300} =0.02777*I_{50}

Substitute the know intensity at 50m we get

I_{300} =0.02777(0.1W/m^{2} )\\I_{300} =2777.7uW/m^{2}  

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If you run 12m/s for 15 minutes, how far will you go explain?
Aneli [31]
To determine the distance that you would travel by.

Simply convert 15 minutes to seconds which would be 900 seconds.

Then solve for distance, which would be

D = r • t
D = 12 m/s • 900 s

D =10 800 m.

This is the distance that you had ran for.
7 0
3 years ago
A man runs for an hour and a half at 8 miles an hour due south. He then continues south on a bus traveling at 55 miles an hour f
bezimeni [28]

Answer:34 miles

Explanation:

Given

Man runs for t_1=1.5\ hr to south with speed v_1=8\ mph

He then continues south for t_2=24\ minutes\approx 0.4\ hr with speed v_2=55\ mph

Total distance traveled d=v_1\times t_1+v_2\times t_2

d=8\times 1.5+55\times 0.4

d=12+22

d=34\ miles

thus he travels a distance of 34\ miles due to south

3 0
3 years ago
A gas at 110atm and 303K filled a container of 2L. If the temperature is raised to 353 K and the pressure is increased to 440atm
Sveta_85 [38]

Answer:

0.58 L

Explanation:

For this problem we need to simply use the ideal gas equation to create a proportional comparison for the initial information to the final information.

(P_1 * V_1) / T_1 = (P_2 * V_2) / T_2

Using this, we can solve for V_2 to find the new volume of the gas once pressure and temperature changes.

(P_1 * V_1) * T_2 / T_1 = (P_2 * V_2)

(P_1 * V_1) * T_2 / (T_1 * P_2) = V_2

Consider our givens:

P_1 = 110atm

T_1 = 303K

V_1 = 2L

P_2 = 440atm

T_2 = 353K

Now we simply plug in these values to the equation to find the new volume, V_2.

(P_1 * V_1) * T_2 / (T_1 * P_2) = V_2

(110atm * 2L) * 353K / (303K * 440atm) = V_2

77660 atm*L*K / 133320 K*atm = V_2

0.583 L = V_2

Hence, the new volume is 0.583 L.

Cheers.

4 0
2 years ago
You, Archimedes, suspect that the king’s crown is not solid gold but is instead gold-plated lead. To test your theory, you weigh
hjlf

Answer:

a) 16675.75 Kg/m³ b) 77.6%

Explanation:

the weight of the crown = 60 N, density of gold = 19300 Kg/m^3, density of lead = 11340 kg/m^3, density of water = 1000kg/m^3 and acceleration due to gravity = 9.8 m/s^2

upthrust on the crown = weight in air - weight when fully submerged in water = 60 - 56.4 = 3.6 N

mass of water displaced = 3.6 / 9.8  since weight = mass × g

mass of water displaced = 0.367 Kg

density of water = mass / volume

1000 = 0.367 / volume

cross multiply and find volume

volume of the crown = 0.367 / 1000 = 0.000367 m³ since the crown will displace water of equal volume according to Archimedes principle

Let V1 represent the volume of Gold and let V2 represent the volume of lead

Total volume of the crown = V1 + V2

also

density of gold = mass of gold / V1 and density of lead = mass of lead / V2

19300 = mass of gold in the crown / V1 and 11340 = mass of lead in the crown / V2

19300 V1 = mass of gold and 11340 V2 = mass of lead

add the two together

19300 V1 + 11340 V2 = weigth of the crown / 9.8

19300 V1 + 11340 V2 = 6.12 also

V1 + V2 = 0.000367

make V1 subject of the formula in equation 2

V1 = 0.000367 - V2

substitute for V1 in equation 1

19300 (0.000367 - V2) + 11340 V2 = 6.12

open the bracket

7.083 - 19300 V2 + 11340 V2 = 6.12

rearrange the equation

-7960 V2 = 6.12 - 7.083  

-7960 V2 = -0.963

V2 = -0.963 / -7960 = 0.000121 (volume of lead in the crown)

substitute V2 into equation 2

V1 + 0.000121  = 0.000367m³

V1 = 0.000367 - 0.000121 = 0.000246m³ (volume of gold in the crown)

so mass of gold in the crown = 19300 × 0.000246 = 4.748 kg

and mass of lead = 11340 × 0.000121 = 1.372 kg

average density of the crown = (mass of gold + mass of lead) / total volume = 6.12 / 0.000367 = 16675.75 kg/ m³

b) percentage make of gold = mass of gold / total mass × 100 = 77.6 % approx

4 0
3 years ago
The Burj Khalifa in Dubai is the world's tallest building. The structure is 828 m (2,716.5 feet) and has more than 160 stories.
Elena L [17]

Answer:

 h = 599.5 m

Explanation:

Given,

height of structure = 828 m

weight of the tourist = 184 lb

                                 = 184 x 0.45359 = 83.43 Kg

Potential energy = 187000 J

PE = m gd

d = \frac{PE}{mg}

d = \frac{187000}{83.43\times 9.81}

h = 228.5 m

Height of the room above the ground.

 h = 828 - 228.5

 h = 599.5 m

Height of the floor above ground is equal to 599.5 m.

4 0
3 years ago
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