The power of the engine is 320 W.
<u>Explanation:</u>
Power may be defined as the rate of doing work (or) work done per unit time. One unit of energy is used to do the one unit of work.
Power = Work done / Time taken
Given, Force = 80 N, height = 5 m , final velocity = 4 m/s
To calculate the power, we must know the time taken.
To find the time, use the distance and speed formula which is given by
Time = Distance / speed
Here distance = 5 m and speed = 4 m/s
Time = 5 / 4 = 1.25 s.
Now, Power = work done / time
= (F * d) / t = (80 * 5) / 1.25
Power = 320 W.
The standard unit of power is watt (W) which is joule per second.
Answer:
2. Wavelength
Explanation:
When a photon collides with an electron and is deflected, the photon’s wavelength decreases.
When photon gained energy by the collision of the electron. Its energy and frequency will be increased and its wavelength will be decreased.
Answer:
The required angle is (90-25)° = 65°
Explanation:
The given motion is an example of projectile motion.
Let 'v' be the initial velocity and '∅' be the angle of projection.
Let 't' be the time taken for complete motion.
Let 'g' be the acceleration due to gravity
Taking components of velocity in horizontal(x) and vertical(y) direction.
= v cos(∅)
= v sin(∅)
We know that for a projectile motion,
t =![\frac{2vsin(∅)}{g}](https://tex.z-dn.net/?f=%5Cfrac%7B2vsin%28%E2%88%85%29%7D%7Bg%7D)
Since there is no force acting on the golf ball in horizonal direction.
Total distance(d) covered in horizontal direction is -
d =
×t = vcos(∅)×
=
.
If the golf ball has to travel the same distance 'd' for same initital velocity v = 23m/s , then the above equation should have 2 solutions of initial angle 'α' and 'β' such that -
α +β = 90° as-
d =
=
=
=
.
∴ For the initial angles 'α' or 'β' , total horizontal distance 'd' travelled remains the same.
∴ If α = 25° , then
β = 90-25 = 65°
∴ The required angle is 65°.
Force= mass x acceleration
79=mass(3)
m=79/3
m=26.3 kg
We can determine a planet's orbital period and separation from its star using any detection method. The transit method can yield sizes, whereas the astrometric and doppler approaches can provide minimum masses.
We can calculate average density by combining the transit and doppler approaches. Numerous physical properties, including the semi-major axis, stellar mass, star radius, planet radius, eccentricity, and inclination, are calculated from these observable data. The mass of the planet is also calculated using the star's combined radial velocity readings.
List briefly the planetary characteristics that, in theory, can be detected with the present detection techniques. We can determine a planet's orbital period and separation from its star using any detection method. The transit method can yield sizes, whereas the astrometric and doppler approaches can provide minimum masses.
To know more about orbital period
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