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Dahasolnce [82]
3 years ago
6

Vitamin , cyanocobalamin, is essential for human nutrition. It is concentrated in animal tissue but not in higher plants. Althou

gh nutritional requirements for the vitamin are quite low, people who abstain completely from animal products may develop a deficiency anemia. Cyanocobalamin is the form used in vitamin supplements. It contains 4.34% cobalt by mass. Calculate the molar mass of cyanocobalamin, assuming that there is one atom of cobalt in every molecule of cyanocobalamin.
Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
6 0

Answer:

1360.0 g/mol

Explanation:

If there is one atom of cobalt in every molecule of cyanocobalamin its chemical formula must be

CoX₂, so there is 1 mol of cobalt for 1 mol of the compound. The molar mass of the cobalt is 59 g/mol. So, there is 59 g of cobalt in 1 mol of the cyanocobalamin and it represents 4.34% of the total mass, so:

0.0434m = 59

m = 1359.45 g of cyanocobalamin

The molar mass of the molecule is the mass divided by the number of moles (which is 1), so it is:

M = 1359.45 g/mol = 1360.0 g/mol

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675 g of carbon tetrabromide is equivalent to how many
VARVARA [1.3K]
<h3>Answer:</h3>

2.04 mol CBr₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Organic</u>

  • Writing Organic Compounds
  • Writing Covalent Compounds
  • Organic Prefixes

<u>Atomic Structure</u>

  • Reading a Periodic Table
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<h3>Explanation:</h3>

<u>Step 1: Define</u>

675 g CBr₄

<u>Step 2: Identify Conversions</u>

Molar Mass of C - 12.01 g/mol

Molar Mass of Br - 79.90 g/mol

Molar Mass of CBr₄ - 12.01 + 4(79.90) = 331.61 g/mol

<u>Step 3: Convert</u>

<u />\displaystyle 675 \ g \ CBr_4(\frac{1 \ mol \ CBr_4}{331.61 \ g \ CBr_4}) = 2.03552 \ mol \ CBr_4<u />

<u />

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

2.03552 mol CBr₄ ≈ 2.04 mol CBr₄

7 0
3 years ago
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There are two isotopes of an unknown element, X-19 and X-21. The abundance of X-19 is 14.55%. A weighted average uses the percen
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Answer:

2.765amu is the contribution of the X-19 isotope to the weighted average

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The average molar mass is defined as the sum of the molar mass of each isotope times its abundance. For the unknown element X that has 2 isotopes the weighted average is defined as:

X = Mass X-19 * Abundance X-19 + MassX-21 * Abundance X-21

The contribution of the X-19 isotope is its mass (19.00 amu) times its abundance (14.55% = 0.1455). That is:

19.00amu * 0.1455 =

2.765amu is the contribution of the X-19 isotope to the weighted average

8 0
2 years ago
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