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tresset_1 [31]
3 years ago
10

Water is unique because the density of it's solid is less than the density of it's liquid. Describe how life would be different

if this weren't true
Chemistry
1 answer:
Andreas93 [3]3 years ago
6 0

Ice caps would float therefore providing insulation for aquatic life and ensuring they do not freeze due to the cool temperature.

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How many cm3 are contained in 3.83 x 107 mm3?
gulaghasi [49]

Answer:

3.38 x 10⁴cm³

Explanation:

Given that:

      Volume of the substance  = 3.83 x 10⁷mm³

The problem entails use to convert from mm³ to cm³;

                    1000mm³   = 1cm³

So;

          3.83 x 10⁷mm³ will produce \frac{ 3.83 x 10^{7} }{1000}    = 3.38 x 10⁴cm³

5 0
3 years ago
What is the ph of a 0.45 m solution of aniline (c6h5nh2)? (pkb  9.40)?
mote1985 [20]

Answer is: pH of aniline is 9.13.<span>
Chemical reaction: C</span>₆H₅NH₂(aq)+ H₂O(l) ⇌ C₆H₅NH₃⁺(aq) + OH⁻(aq).

pKb(C₆H₅NH₂) = 9.40.

Kb(C₆H₅NH₂) = 10∧(-9.4) = 4·10⁻¹⁰.

c₀(C₆H₅NH₂) = 0.45 M.

c(C₆H₅NH₃⁺) = c(OH⁻) = x.

c(C₆H₅NH₂) = 0.45 M - x.

Kb = c(C₆H₅NH₃⁺) · c(OH⁻) / c(C₆H₅NH₂).

4·10⁻¹⁰ = x² /  (0.45 M - x). 

Solve quadratic equation: x = c(OH⁻) = 0.0000134 M.

pOH = -log(0.0000134 M.) = 4.87.

pH = 14 - 4.87 = 9.13.

7 0
3 years ago
Match the Terms to their definition:
olganol [36]
1. B
2. H
3. G
4. I
5. D
6. C
7. A
8. F
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I am not sure weather it is correct but I wrote what I know
3 0
3 years ago
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To make 2.00 L of 0.300 M sulfuric acid, how many mL of a 1.00 M stock solution should be used?
Tamiku [17]
We are given with
M1 = 1.00 M

M2 = 0.300 M
V2 = 2.00 L

We are asked to get V1

Using material balance
M1 V1 = M2 V2
Substituting the given values
1.00 V1 = 0.300 M (2.00 L)
V1 = 0.600 L or 600 mL
THe volume needed is 600 mL<span />
3 0
3 years ago
Elena makes the table below to determine the number of atoms of each element in the chemical formula 3(NH4)2SO4
frozen [14]

Answer:

she should not have multiplied the sulfur atoms by the subscript 4

Explanation:

5 0
3 years ago
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