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Amiraneli [1.4K]
3 years ago
11

which shows as evidence for a scientific claim. A- surveys of public opinion B- company advertisments C-controlled experiments D

- personal websites
Chemistry
2 answers:
Lena [83]3 years ago
7 0

Answer:

A

You do not know if the advertisement is lying to you. Controlled experiments will be biased and personal websites will say what they think, not following the data & science.

Kryger [21]3 years ago
3 0

Answer:

I think it is A.

The rest can be biased.

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In ionic bonding an arrow is often drawn on the diagram. What does
alexandr1967 [171]

In ionic bonding, an arrow is often drawn on the diagram to show the direction the electrons move to form the ions.

4 0
3 years ago
A balloon is filled to a volume of 1.50 L with 3.00 moles of gas at 25 °C. With pressure and temperature held constant, what wil
Ludmilka [50]

Answer:

Volume : 1.25 L

Explanation:

We are given here that the volume ( V_1 ) = 1.50 Liters, the initial moles ( held at 25 °C ) = 3.00 mol, and the final moles ( n_2 ) = 3.00 - 0.5 = 2.5 mol. The final mol is calculated given that 0.50 mol of gas are released from the prior 3.00 moles of gas.

Volume ( V_1 ) = 1.50 L,

Initial moles ( n_1 ) = 3.00 mol,

Final Volume ( n_2 ) = 3.00 - 0.5 = 2.5 mol

Applying the combined gas law, we can calculate the final volume ( V_2 ).

P_1V_1 / n_1T_1 = P_2V_2 / n_2T_2 - we know that the pressure and temperature are constant, and therefore we can apply the following formula,

V_1 / n_1 = V_2 / n_2 - isolate V_2,

V_2 = V_1 n_2 / n_1 = 1.50 L * 2.5 mol / 3.00 mol = ( 1.5 * 2.5 / 3 ) L = 1.25 L

The volume of the balloon will be 1.25 L.

6 0
3 years ago
A science fair volcano bubbles and fizzes. what is taking place?
vaieri [72.5K]
Answer is B. gas formation
7 0
3 years ago
according to iupac nomeclature rules which set of chemical name and formula for the same compound is correct?
kumpel [21]

Answer:

stock and traditional

Explanation:

the iupac says so

5 0
2 years ago
What is the mass, in grams, of 1.4 mol W
algol [13]
Atomic mass W = 183.84 u.m.a

1 mole --------- 183.84
1.4 moles ---- ?

1.4 x 183.84 / 1 = 257.376 g

hope this helps!
3 0
3 years ago
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