Below is the correct formula unit for Sodium Chloride
2 answers:
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Explanation:
As is a covalent compound because it is made up by the combination of two non-metal atoms. Atomic number of an iodine atom is 53 and it contains 7 valence electrons as it belongs to group 17 of the periodic table.
Therefore, sharing of electrons will take place when two iodine atoms chemically combine with each other leading to the formation of a covalent bonding.
Hence, weak forces like london dispersion forces will be present between a molecule of .
The weak intermolecular forces which can arise either between nucleus and electrons or between electron-electron are known as dispersion forces. These forces are also known as London dispersion forces and these are temporary in nature.
thus, we can conclude that london dispersion force is the major attractive force that exists among different molecules in the solid.
Answer:
Explanation:
<h2>Part 1: Naming compound formulas given the names</h2><u>Step 1.</u> Methane's formula is .
<u>Step 2:</u> Oxygen is a diatomic molecule (it exists bonded to itself for stability purposes), so by itself in chemical equations, it is written as .
<u>Step 3:</u> Carbon dioxide is the molecular compound of one atom of carbon and two atoms of oxygen → .
<u>Step 4:</u> Water is the common name of the compound of two hydrogen atoms and one oxygen atom → .
<u>Step 1:</u><em> </em>Use the determined formulas for the reactants and plug them into the equation. We are told that methane burns in oxygen -- hinting at a combustion reaction. Therefore, we may infer that these are the reactants that yield the products.
Skeleton equations are written with the reactant(s) on the left -- if there are several, they are separated by an addition symbol (+).
With this information, we may begin our equation: , where
is methane and
is the diatomic molecule of oxygen.
<u>Step 2:</u> Use the determined formulas for the products and plug them into the equation. We are told that the methane burns in oxygen to produce carbon dioxide and water. Hence, we can separate these two as we did with the reactants.
Now, our products side of the reaction will look like this: , where
is carbon dioxide and
is water.
<u>Step 3:</u> Write the final equation. All you must do after determining both sides of the equation is simply push them together. Place the reactant side of the equation on the left and the product side of the equation on the right.
This gives us our final equation, .
Because the problem asks for the unbalanced equation, we do not need to take any further steps of balancing the equation.